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COMPUTATIONAL PROBLEMS IN ABSTRACT ALGEBRA.

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48 H. Jiirgensen Calculation with elements of a finite group<br />

Because of (Rl), (R2), and (R4) Uj/Uj_l is a finite cyclic group of order<br />

greater than 1; hence G is a finite soluble group.<br />

Now let G be a finite soluble group. If G is cyclic, it will be defined by the<br />

generator aI with glr = e and w1 = IGI. If G is not cyclic, there exists a<br />

finite chain of subgroups UO, UI, . . . , U, of G with: UO = gp(e); U,, = G;<br />

Uj_1 a Uj; Uj/ Ujel is cyclic and finite of order Uj : Uj-, =- 1 (1 =z j < n). For<br />

j = l(l)n aj is selected in such a way that gp( Uj-l, aj) = Uj; yj will be<br />

defined as Uj : Uj-1 ((R4) holds). Then the words gij can be found such<br />

that (Rl), (R2), and (R3) hold. For the proof that G is defined by an AGsystem<br />

chosen like this we define:<br />

Aword a”ma”~-1.. . aEvlc G(1 == vlen; eyi integer; i = l(l)n), for<br />

which the f%ov%g condi?ions hold, is called a normed word:<br />

Vi -c Vi+1; l=siim WI<br />

0 =s EYi; l=si

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