05.01.2013 Views

COMPUTATIONAL PROBLEMS IN ABSTRACT ALGEBRA.

COMPUTATIONAL PROBLEMS IN ABSTRACT ALGEBRA.

COMPUTATIONAL PROBLEMS IN ABSTRACT ALGEBRA.

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

340 J. H. Conway<br />

-thus our symmetry formulae show that a 2-component link can only be<br />

amphicheiral if its polynomial vanishes identically. It seems plain -that<br />

much work remains to be done in this field.<br />

7. Determinants and signature. We define the reduced polynomial DK(x)<br />

by the equation<br />

DK(X) = {x}. V&x, x, . . .),<br />

and the determinant S = 6, as the number a&i). Our determinant differs<br />

from the usual one only by a power of i. The potential identities of the last<br />

section yield determinant identities when we put i for each variable.<br />

Murasugi [7] has defined invariants called the signature, UK, and nullity,<br />

nK, and described some of their properties. These invariants depend on the<br />

string orientations of K, but not on its labelling. We shall describe enough<br />

of their properties to enable their calculation to proceed in much the same<br />

way as that of the potential function.<br />

For any knot K we have the identity<br />

where 6% = /&I, and the condition<br />

ItK =- 1 if and only if aK = 0,<br />

the first of which determines UK modulo 4 provided gK $ 0. But one of<br />

Murasugi’s results is that<br />

whenever K+ and KO are related as in the first identity. These two results<br />

determine 0, completely in almost all cases, and make its calculation very<br />

swift indeed. Of course it should be remembered that a, and nK are integers,<br />

and 1 4 izK=% IKI.<br />

We have the relations<br />

concerning obverses and products, and if we define a$ as oK - A,, where &<br />

is the total linking of K (the sum of the linking numbers of each pair of<br />

distinct strings of K), then the reorienting identity is that &, like Sg, is an<br />

invariant of the unoriented knot K. In the tables, we give only these resid&<br />

invariants, 60 being the numerator of the rational fraction which we give<br />

for rational knots.<br />

8. Slice knots and the cobordism group. A proper knot which can arise<br />

as the central 3-dimensional section of a (possibly knotted) locally flat<br />

2-sphere in 4-space we call a slice knot. A natural application of our tables<br />

is to the discovery of interesting slice knots, since for slice knots there are<br />

simple conditions on the polynomial, signature, and Minkowski units. In<br />

Enumeration of knots and links 341<br />

particular, we might hope to find a slice knot which is not a ribbon knot<br />

[3], since several published proofs that all slice knots are ribbon have been<br />

found to be fallacious.<br />

The slice knots with 10 crossings or less were found to be<br />

-,42, 3113,2312,(3,21,2-),212112,20:20:20,(3,3,21-),<br />

64, 3313,2422,2211112,(41, 3,2),(21,21, 21+);22-20,<br />

a2.2.2 0.2 0, 1 0*, (3 2, 2 1, 2-j, (2 2, 2 1 1, 2-), (4, 3, 2 l-),<br />

((3, 2)-(2 1, 2)), 3 : 2 : 2,<br />

together with the composite knots 3 % 3,2 2 EX 2 2,5 % 5,3 2 % 3 2. The granny<br />

knot 3 % 3 and the knot a2.2.2.2 0 satisfy the polynomial condition but<br />

not the signature condition, and so are not slice knots.<br />

Now suppose that in the slab of 4-space bounded by two parallel 3-spaces<br />

we have an annulus (PXZ) whose boundary circles lie in the two 3-spaces.<br />

Then the two knots defined by these circles we call cobordant. Cobordism is<br />

an equivalence relation, and the cobordism classes form a group under the<br />

product operation, the unit class being the class of slice knots, and the inverse<br />

of any class is the class of inverse knots to the knots of that class.<br />

A search was made for cobordances between knots of at most 10 crossings<br />

and knots of at most 6 crossings, which in addition to the cobordances<br />

between slice knots, found only<br />

3~321223, 21, 2~222112~22, 211, 2~31, 3, 21~211, 3, 21-a<br />

22=3,21,21~3,21,2+<br />

5r3412r4,3,21<br />

32~31,3,21~3,3,21+r3,21,2++<br />

3 % 3 “= .2.2.2.2 0,<br />

all of these being to within sign and orientation.<br />

All slice knots given were found to be ribbon knots. However, thepresence<br />

of the particular knot lO* = (2 X 5)* leads us to examine the more<br />

general a strand b bight Turk’s Head knot ((a - 1) x b)*. Andrew Tristram<br />

has proved that if a and b are odd and coprime this knot obeys all known<br />

algebraic conditions for slice knots, but despite a prolonged attack the only<br />

cases definitely known to be slice are the trivial cases with a or b = 1, and<br />

the cases a = 3, b = 5, and a = 5, b = 3. Since most of our methods for<br />

proving knots slice would also prove them ribbon, the way is left open for<br />

a conjecture that some of least of these are slice knots which are not ribbon<br />

knots.<br />

9. Notes on the tables. Acknowledgments. The tables (pp. 343-357) list<br />

all proper knots of at most 11 crossings, and all links of at most 10 crossings,<br />

with various invariants tabulated over parts of this range. Knots<br />

listed separately are believed to be distinct, and the symmetries listed<br />

under S are believed to be a complete set. (The evidence is very strong-

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!