vdoc
Chapter 3: C. Basic Geometry 23Table 3.2 Calculation of perimeter and circumference of basic geometric shapes. ContinuedShape Example FormulaCircleDrCircumference = 2p r = p Dwhere r is radius andD is diameter.Part I.CA parallelogram has two sides equal to 26 mm and a top andbase each equal to 40 mm. Its perimeter is (2 × 26 mm) + (2 × 40 mm)= 132 mm.A trapezoid has sides of length 12, 15, 24, and 27 cm. Its perimeter isthen (12 cm + 15 cm + 24 cm + 27 cm) = 78 cm.A regular hexagon (meaning one with all sides the same length) hassides of length 8.0 cm. Its perimeter is then 6 × 8.0 cm = 48.0 cm.A right triangle (meaning that the triangle has a 90-degree angle) hasa base of 65 mm, a height of 120 mm, and a hypotenuse of 136.47 mm.Its perimeter is (65 mm + 120 mm + 136.47 mm) = 321.47 mm.A triangle has sides with lengths 20 cm, 34 cm, and 40 cm. Its perimeteris (20 cm + 34 cm + 40 cm) = 94 cm.A circle has a radius of 25 inches, hence a diameter of 50 inches. Itscircumference is (2 × p × 25 in) = (p × 50 in) = 157.08 in. Note: sincethe formula involves pi, when at all possible use a calculator to findcircumference to avoid round-off errors.VOLUME OF BASIC GEOMETRIC SHAPESVolume (V) is expressed in terms of cubic units, such as cm 3 or ft 3 . Formulas forcalculating volume are shown in Table 3.3.Examples of Volume CalculationsA square prism has length, width, and height equal to 23 cm, 12 cm, and30 cm, respectively. Its volume is (23 cm × 12 cm × 30 cm) = 8280 cm 3 .A cube has sides of length 13 inches. Its volume is then (13 in) 3 = (13 in ×13 in × 13 in) = 2197 in 3 .
24 Part I: Technical MathematicsTable 3.3 Calculation of volume of basic geometric shapes.Shape Example FormulaPart I.CSquare prismcV = abcabCube (all sides V = s 3equal length)sCylinderrV = p r 2 hhrCone V = 1 2p r h3hSphere V = 4 p r3r3A cylinder has a radius of 120 mm and a height of 250 mm. Its volume isp × (120 mm) 2 × (250 mm) = 11,309,734 mm 3 . Note: since the formulainvolves pi, when at all possible use a calculator to find the volume ofa cylinder to avoid round-off errors.A cone has a radius of 3.5 inches and a height of 12 inches. Its volume is(1/3) × p × (3.5 in) 2 × 12 in = 153.938 in 3 . Note: since the formula involvespi (p), when at all possible use a calculator to find the volume of a coneto avoid round-off errors.
- Page 1 and 2: The Certified QualityInspector Hand
- Page 3 and 4: PrefaceThe quality inspector is the
- Page 5 and 6: Glossary of Inspection Terms 421min
- Page 7 and 8: Table of ContentsList of Figures an
- Page 9 and 10: Table of Contents xi5. Normal Distr
- Page 11 and 12: Part I.AChapter 1A. Basic Shop Math
- Page 13 and 14: 4 Part I: Technical MathematicsEqui
- Page 15 and 16: 6 Part I: Technical MathematicsLeas
- Page 17 and 18: 8 Part I: Technical Mathematics3= 3
- Page 19 and 20: 10 Part I: Technical MathematicsEve
- Page 21 and 22: Part I.BChapter 2B. Basic AlgebraSo
- Page 23 and 24: 14 Part I: Technical MathematicsAlw
- Page 25 and 26: 16 Part I: Technical MathematicsPar
- Page 27 and 28: 18 Part I: Technical MathematicsChe
- Page 29 and 30: 20 Part I: Technical MathematicsTab
- Page 31: 22 Part I: Technical MathematicsTab
- Page 35 and 36: 26 Part I: Technical MathematicsExa
- Page 37 and 38: 28 Part I: Technical MathematicsPyt
- Page 39 and 40: 30 Part I: Technical MathematicsTab
- Page 41 and 42: 32 Part I: Technical MathematicsPar
- Page 43 and 44: 34 Part I: Technical MathematicsThi
- Page 45 and 46: 36 Part I: Technical MathematicsTwo
- Page 47 and 48: 38 Part I: Technical MathematicsAng
- Page 49 and 50: 40 Part I: Technical MathematicsTab
- Page 51 and 52: 42 Part I: Technical MathematicsTab
- Page 53 and 54: 44 Part I: Technical MathematicsTab
- Page 55 and 56: 46 Part I: Technical MathematicsPar
- Page 57 and 58: 48 Part I: Technical MathematicsPar
- Page 59 and 60: 50 Part I: Technical MathematicsTab
- Page 61 and 62: 52 Part I: Technical MathematicsNeg
- Page 63 and 64: 54 Part I: Technical MathematicsCon
- Page 65 and 66: Part IIMetrologyChapter 7Chapter 8C
- Page 67 and 68: Chapter 7: A. Common Gages and Meas
- Page 69 and 70: Chapter 7: A. Common Gages and Meas
- Page 71 and 72: Chapter 7: A. Common Gages and Meas
- Page 73 and 74: Chapter 7: A. Common Gages and Meas
- Page 75 and 76: Chapter 7: A. Common Gages and Meas
- Page 77 and 78: Chapter 7: A. Common Gages and Meas
- Page 79 and 80: Chapter 7: A. Common Gages and Meas
- Page 81 and 82: Chapter 8B. Special Gages and Appli
Chapter 3: C. Basic Geometry 23
Table 3.2 Calculation of perimeter and circumference of basic geometric shapes. Continued
Shape Example Formula
Circle
D
r
Circumference = 2p r = p D
where r is radius and
D is diameter.
Part I.C
A parallelogram has two sides equal to 26 mm and a top and
base each equal to 40 mm. Its perimeter is (2 × 26 mm) + (2 × 40 mm)
= 132 mm.
A trapezoid has sides of length 12, 15, 24, and 27 cm. Its perimeter is
then (12 cm + 15 cm + 24 cm + 27 cm) = 78 cm.
A regular hexagon (meaning one with all sides the same length) has
sides of length 8.0 cm. Its perimeter is then 6 × 8.0 cm = 48.0 cm.
A right triangle (meaning that the triangle has a 90-degree angle) has
a base of 65 mm, a height of 120 mm, and a hypotenuse of 136.47 mm.
Its perimeter is (65 mm + 120 mm + 136.47 mm) = 321.47 mm.
A triangle has sides with lengths 20 cm, 34 cm, and 40 cm. Its perimeter
is (20 cm + 34 cm + 40 cm) = 94 cm.
A circle has a radius of 25 inches, hence a diameter of 50 inches. Its
circumference is (2 × p × 25 in) = (p × 50 in) = 157.08 in. Note: since
the formula involves pi, when at all possible use a calculator to find
circumference to avoid round-off errors.
VOLUME OF BASIC GEOMETRIC SHAPES
Volume (V) is expressed in terms of cubic units, such as cm 3 or ft 3 . Formulas for
calculating volume are shown in Table 3.3.
Examples of Volume Calculations
A square prism has length, width, and height equal to 23 cm, 12 cm, and
30 cm, respectively. Its volume is (23 cm × 12 cm × 30 cm) = 8280 cm 3 .
A cube has sides of length 13 inches. Its volume is then (13 in) 3 = (13 in ×
13 in × 13 in) = 2197 in 3 .