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Oscillations, Waves, and Interactions - GWDG

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Acoustic cavitation 179<br />

λ =1 λ=10<br />

Figure 6. Stability of a spherical bubble with respect to parametric surface mode instability<br />

in the parameter plane of equilibrium radius R0 <strong>and</strong> driving pressure amplitude pa; driving<br />

frequency 15 kHz. Colors indicate the stability with respect to the modes n = 2, 3, <strong>and</strong> 4.<br />

Black: all modes stable, darkest blue: one mode unstable, blue: two modes unstable, <strong>and</strong><br />

light blue: all three modes unstable. Left: maximum allowed stable eigenvalue λ = 1, right:<br />

λ = 10. At higher driving, all but very small bubbles (below the dynamic Blake threshold)<br />

become unstable.<br />

cally excited linear oscillator systems, which are for periodic radial oscillation of the<br />

type of Hill’s differential equation. If am denotes the amplitude of the m-th surface<br />

mode, its equation of motion reads<br />

+(m − 1)<br />

�<br />

äm +<br />

�<br />

3 ˙ R<br />

µ<br />

+ 2(m + 2)(2m + 1)<br />

R<br />

ρR 2<br />

(m + 1)(m + 2) σ<br />

ρR 3 − ¨ R<br />

R + 2(m + 2) µ ˙ R<br />

ρR 3<br />

�<br />

�<br />

˙am<br />

am = 0 .<br />

Here, the solution of the spherical bubble model, R(t), enters as the parametric driving.<br />

The bubble is considered to be spherically unstable, if at least one surface mode<br />

amplitude reaches the actual bubble radius value (Rayleigh-Taylor instability 7 ) or<br />

grows indefinitely in time (parametric instability). For simplicity, only the latter case<br />

is considered in the following. It is easily calculated numerically by integrating the<br />

spherical bubble model together with the linear mode amplitude equations. Because<br />

of linearity of the latter, it is sufficient for a periodic radial motion to integrate over<br />

one period <strong>and</strong> calculate the Floquet multipliers (eigenvalues of the “monodromy<br />

matrix”, see Ref. [26]). If the absolute value of at least one mode is larger than one,<br />

formally that mode would grow <strong>and</strong> finally destroy the bubble. In reality, the linearization<br />

breaks down from some point on, <strong>and</strong> mode coupling would lead to energy<br />

redistribution, also to the fundamental mode. Without considering this issue here in<br />

7 For this calculation, one has to assume an initial size of a disturbance of the spherical<br />

form, <strong>and</strong> the outcome slightly depends on this choice.

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