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Essential Cell Biology 5th edition

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Answers A:43

ANSWER 16–14 Activation in both cases depends

on proteins that catalyze GDP–GTP exchange on the

G protein or Ras protein. Whereas activated GPCRs

perform this function directly for G proteins, enzymelinked

receptors assemble multiple signaling proteins into

a signaling complex when the receptors are activated by

phosphorylation; one of these proteins is an adaptor protein

that recruits a guanine nucleotide exchange factor that

fulfills this function for Ras.

ANSWER 16–15 Because the cytosolic concentration of

Ca 2+ is so low, an influx of relatively few Ca 2+ ions leads

to large changes in its cytosolic concentration. Thus, a

tenfold increase in cytosolic Ca 2+ can be achieved by

raising its concentration into the micromolar range, which

would require far fewer ions than would be required to

change significantly the cytosolic concentration of a more

abundant ion such as Na + . In muscle, a greater than tenfold

change in cytosolic Ca 2+ concentration can be achieved

in microseconds by releasing Ca 2+ from the sarcoplasmic

reticulum, a task that would be difficult to accomplish if

changes in the millimolar range were required.

ANSWER 16–16 In a multicellular organism such as an

animal, it is important that cells survive only when and

where they are needed. Having cells depend on signals

from other cells may be a simple way of ensuring this. A

misplaced cell, for example, would probably fail to get

the survival signals it needs (as its neighbors would be

inappropriate) and would therefore kill itself. This strategy

can also help regulate cell numbers: if cell type A depends

on a survival signal from cell type B, the number of B cells

could control the number of A cells by making a limited

amount of the survival signal, so that only a certain number

of A cells could survive. There is indeed evidence that such a

mechanism does operate to help regulate cell numbers—in

both developing and adult tissues (see Figure 18–41).

ANSWER 16–17 Ca 2+ -activated Ca 2+ channels create

a positive feedback loop: the more Ca 2+ that is released,

the more Ca 2+ channels that open. The Ca 2+ signal in the

cytosol is therefore propagated explosively throughout the

cardiac muscle cell, thereby ensuring that all myosin–actin

filaments contract almost synchronously.

ANSWER 16–18 K2 activates K1. If K1 is permanently

activated, a response is observed regardless of the status of

K2. If the order were reversed, K1 would need to activate

K2, which cannot occur because in our example K2 contains

an inactivating mutation.

ANSWER 16–19

A. Three examples of extended signaling pathways to the

nucleus are: (1) extracellular signal → RTK → adaptor

protein → Ras-activating protein → MAP kinase

kinase kinase → MAP kinase kinase → MAP kinase →

transcription regulator; (2) extracellular signal → GPCR

→ G protein → phospholipase C → IP 3 → Ca 2+ →

calmodulin → CaM-kinase → transcription regulator;

(3) extracellular signal → GPCR → G protein → adenylyl

cyclase → cyclic AMP → PKA → transcription regulator.

B. An example of a direct signaling pathway to the nucleus

is Delta → Notch → cleaved Notch tail → transcription.

ANSWER 16–20 When PI 3-kinase is activated by

an activated RTK, it phosphorylates a specific inositol

phospholipid in the plasma membrane. The resulting

phosphorylated inositol phospholipid then recruits to the

plasma membrane both Akt and another protein kinase that

helps phosphorylate and activate Akt. A third kinase that

is permanently associated with the membrane also helps

activate Akt (see Figure 16−32).

ANSWER 16–21 Polar groups are hydrophilic, so

cholesterol, with only one polar –OH group, would be too

hydrophobic to be an effective hormone by itself. Because

it is virtually insoluble in water, it could not move readily as

a messenger from one cell to another via the extracellular

fluid, unless carried by specific proteins.

ANSWER 16–22 In the case of the steroid-hormone

receptor, a one-to-one complex of steroid and receptor

binds to DNA to activate or inactivate gene transcription;

there is thus no amplification between ligand binding

and transcriptional regulation. Amplification occurs later,

because transcription of a gene gives rise to many mRNAs,

each of which is translated to give many copies of the

protein it encodes (discussed in Chapter 7). For the ionchannel-coupled

receptor, a single ion channel will let

through thousands of ions in the time it remains open; this

serves as the amplification step in this type of signaling

system.

ANSWER 16–23 The more steps there are in an

intracellular signaling pathway, the more places the cell

has to regulate the pathway, amplify the signal, integrate

signals from different pathways, and spread the signal along

divergent paths (see Figure 16−9).

ANSWER 16–24 Animals and plants are thought to

have evolved multicellularity independently, and therefore

will be expected to have evolved some distinct signaling

mechanisms for their cells to communicate with one another.

On the other hand, animal and plant cells are thought to

have evolved from a common eukaryotic ancestor cell,

and so plants and animals would be expected to share

some intracellular signaling mechanisms that the common

ancestor cell used to respond to its environment.

Chapter 17

ANSWER 17–1 Cells that migrate rapidly from one place

to another, such as amoebae (A) and sperm cells (F), do not

in general need intermediate filaments in their cytoplasm,

since they do not develop or sustain large tensile forces.

Plant cells (G) are pushed and pulled by the forces of wind

and water, but they resist these forces by means of their

rigid cell walls rather than by their cytoskeleton. Epithelial

cells (B), smooth muscle cells (C), and the long axons of

nerve cells (E) are all rich in cytoplasmic intermediate

filaments, which prevent them from rupturing as they are

stretched and compressed by the movements of their

surrounding tissues. All of the above eukaryotic cells

possess intermediate filaments in their nuclear lamina.

Bacteria, such as Escherichia coli (D), have none whatsoever.

ANSWER 17–2 Two tubulin dimers have a lower affinity for

each other (because of a more limited number of interaction

sites) than a tubulin dimer has for the end of a microtubule

(where there are multiple possible interaction sites, both

end-to-end for tubulin dimers adding to a protofilament,

and side-to-side for the tubulin dimers interacting with

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