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33 Years NEET-AIPMT Chapterwise Solutions - Physics 2020

All previous year questions , and these are downloaded from the sources in the internet. I don't own these resources and these are copyrighted by MTG.

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Semiconductor Electronics : Materials, Devices and Simple Circuits

139

\ Wavelength of light emitted,

1242 eV-nm

λ= = 654 nm

19 . eV

53. (a) : The V-I characteristic for a solar cell is as

shown in the figure.

54. (a) :

Here, Y = A+ B = AB ⋅ = AB ⋅

This AND Gate. So, the truth table is

A B Y

0 0 0

0 1 0

1 0 0

1 1 1

60. (d) : LED bulb will light up if switch(s) A or B or

both A and B is/are open. Hence it represents a NAND

gate.

61. (b) :

The voltage drop across 1 kW = V Z = 15 V

The current through 1 kW is

15 V

−3

I′ = = 15 × 10 A=

15 mA

1 ×

3

10 Ω

The voltage drop across 250 W = 20 V – 15 V

= 5V

The current through 250 W is

5 V

I = = 002A=

20 mA

250 Ω .

The current through the zener diode is

I Z = I – I′ = (20 – 15)mA = 5 mA

55. (c) : Band gap = 2.5 eV

The wavelength corresponding to 2.5 eV

12400 eV Å

= = 4960Å.

2.5 eV

4000 Å can excite this.

56. (d) : Band gap = 2 eV.

Wavelength of radiation corresponding to this energy,

hc 12400 eVÅ

λ= = = 6200Å

E 2 eV

The frequency of this radiation

8

c 3×

10 m/s

= =

λ 6200 × 10

− ⇒ u = 5 × 10

10

14 Hz.

m/s

57. (c) : Zener diode is used for stabilisation while p-n

junction diode is used for rectification.

58. (b) : In photocell, photoelectromotive force,

is the force that stimulates the emission of an electric

current when photovoltaic action creates a potential

difference between two points and the electric current

depends on the intensity of incident light.

59. (a) : A A

B

B

Y

62. (b) :

Y = ( A⋅ B+ A⋅B)

At output, the truth table corresponds to NOR gate.

63. (c) :

Y = ( ABC ) = ABC

If A= B= C= 0then

Y0

= 0=

1

If A= B= C= 0then

Y1

= 1=

0

64. (b) :

Output of the circuit, Y = (A + B)·C

Y = 1 if C = 1 and A = 0, B = 1

or A = 1, B = 0 or A = B = 1

65. (a) :

The output of the given logic circuit is

66. (a) :

X = AB . = AB .

The output of the given logic gate is

C= A⋅ B= A⋅B

It is the Boolean expression of AND gate.

Hence, the resulting gate is a AND gate.

67. (a) : The truth table of the given waveform is as

shown in the table.

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