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College Trigonometry, 2011a

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10.2 The Unit Circle: Cosine and Sine 733<br />

right angle) is called the hypotenuse. We now imagine drawing this triangle in Quadrant I so that<br />

the angle θ is in standard position with the adjacent side to θ lying along the positive x-axis.<br />

y<br />

c<br />

P (a, b)<br />

θ<br />

c<br />

b<br />

θ<br />

c<br />

x<br />

a<br />

According to the Pythagorean Theorem, a 2 + b 2 = c 2 , so that the point P (a, b) lies on a circle of<br />

radius c. Theorem10.3 tells us that cos(θ) = a c and sin(θ) = b c<br />

, so we have determined the cosine<br />

and sine of θ in terms of the lengths of the sides of the right triangle. Thus we have the following<br />

theorem.<br />

Theorem 10.4. Suppose θ is an acute angle residing in a right triangle. If the length of the<br />

side adjacent to θ is a, the length of the side opposite θ is b, andthelengthofthehypotenuse<br />

is c, then cos(θ) = a c and sin(θ) =b c .<br />

Example 10.2.8. Find the measure of the missing angle and the lengths of the missing sides of:<br />

30 ◦ 7<br />

Solution. The first and easiest task is to find the measure of the missing angle. Since the sum of<br />

angles of a triangle is 180 ◦ , we know that the missing angle has measure 180 ◦ − 30 ◦ − 90 ◦ =60 ◦ .<br />

We now proceed to find the lengths of the remaining two sides of the triangle. Let c denote the<br />

length of the hypotenuse of the triangle. By Theorem 10.4, wehavecos(30 ◦ )= 7 c ,orc = 7<br />

cos(30 ◦ ) .<br />

Since cos (30 ◦ √<br />

)= 3<br />

2 , we have, after the usual fraction gymnastics, c = 14√ 3<br />

3<br />

. At this point, we<br />

have two ways to proceed to find the length of the side opposite the 30 ◦ angle, which we’ll denote<br />

b. We know the length of the adjacent side is 7 and the length of the hypotenuse is 14√ 3<br />

3<br />

,sowe

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