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College Trigonometry, 2011a

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726 Foundations of <strong>Trigonometry</strong><br />

y<br />

y<br />

θ<br />

π<br />

1<br />

θ<br />

1<br />

α<br />

1<br />

x<br />

α<br />

1<br />

x<br />

Visualizing θ = π + α<br />

θ has reference angle α<br />

(b) Rewriting θ =2π − α as θ =2π +(−α), we can plot θ by visualizing one complete<br />

revolution counter-clockwise followed by a clockwise revolution, or ‘backing up,’ of α<br />

radians. We see that α is θ’s reference angle, and since θ is a Quadrant IV angle, the<br />

Reference Angle Theorem gives: cos(θ) = 5<br />

13<br />

and sin(θ) =−<br />

12<br />

13 .<br />

y<br />

y<br />

θ<br />

1<br />

θ<br />

1<br />

2π<br />

−α<br />

1<br />

x<br />

α<br />

1<br />

x<br />

Visualizing θ =2π − α<br />

θ has reference angle α<br />

(c) Taking a cue from the previous problem, we rewrite θ =3π − α as θ =3π +(−α). The<br />

angle 3π represents one and a half revolutions counter-clockwise, so that when we ‘back<br />

up’ α radians, we end up in Quadrant II. Using the Reference Angle Theorem, we get<br />

cos(θ) =− 5<br />

13<br />

and sin(θ) =<br />

12<br />

13 .

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