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College Trigonometry, 2011a

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11.4 Polar Coordinates 931<br />

45.<br />

(<br />

)<br />

− 3 10 , −3√ 3<br />

10<br />

46. ( − √ 5, − √ 5 ) 47. (6, 8) 48. ( √ 5, 2 √ 5)<br />

49. (−8, 1) 50. (−2 √ 10, 6 √ 10) 51. (−5, −12) 52.<br />

53. (24, −7) 54. (12, −9) 55.<br />

(√ √ )<br />

2 6<br />

4 , 4<br />

56.<br />

( √ )<br />

5<br />

−<br />

15 , −2√ 5<br />

15<br />

( √ )<br />

65<br />

−<br />

5 , 2√ 65<br />

5<br />

In Exercises 57 - 76, convert the equation from rectangular coordinates into polar coordinates.<br />

Solve for r in all but #60 through #63. In Exercises 60 - 63, you need to solve for θ<br />

57. x = 6 58. x = −3 59. y = 7 60. y =0<br />

61. y = −x 62. y = x √ 3 63. y =2x 64. x 2 + y 2 =25<br />

65. x 2 + y 2 = 117 66. y =4x − 19 67. x =3y + 1 68. y = −3x 2<br />

69. 4x = y 2 70. x 2 + y 2 − 2y = 0 71. x 2 − 4x + y 2 = 0 72. x 2 + y 2 = x<br />

73. y 2 =7y − x 2 74. (x +2) 2 + y 2 =4<br />

75. x 2 +(y − 3) 2 =9<br />

(<br />

76. 4x 2 +4 y −<br />

2) 1 2<br />

=1<br />

In Exercises 77 - 96, convert the equation from polar coordinates into rectangular coordinates.<br />

77. r = 7 78. r = −3 79. r = √ 2 80. θ = π 4<br />

81. θ = 2π 3<br />

82. θ = π 83. θ = 3π 2<br />

84. r = 4 cos(θ)<br />

85. 5r = cos(θ) 86. r =3sin(θ) 87. r = −2sin(θ) 88. r = 7 sec(θ)<br />

89. 12r = csc(θ) 90. r = −2 sec(θ) 91. r = − √ 5 csc(θ) 92. r = 2 sec(θ) tan(θ)<br />

93. r = − csc(θ) cot(θ) 94. r 2 =sin(2θ) 95. r =1− 2 cos(θ) 96. r =1+sin(θ)<br />

97. Convert the origin (0, 0) into polar coordinates in four different ways.<br />

98. With the help of your classmates, use the Law of Cosines to develop a formula for the distance<br />

between two points in polar coordinates.

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