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College Trigonometry, 2011a

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10.6 The Inverse Trigonometric Functions 847<br />

220. f(x) =− cos(x) − 2 √ 2sin(x) 221. f(x) =2sin(x) − cos(x)<br />

In Exercises 222 - 233, find the domain of the given function. Write your answers in interval<br />

notation.<br />

222. f(x) = arcsin(5x)<br />

( ) 3x − 1<br />

223. f(x) = arccos<br />

2<br />

224. f(x) =arcsin ( 2x 2)<br />

( )<br />

( )<br />

1<br />

2x<br />

225. f(x) = arccos<br />

x 2 226. f(x) = arctan(4x) 227. f(x) = arccot<br />

− 4<br />

x 2 − 9<br />

228. f(x) = arctan(ln(2x − 1)) 229. f(x) = arccot( √ 2x − 1) 230. f(x) = arcsec(12x)<br />

( ) x<br />

3<br />

231. f(x) = arccsc(x +5) 232. f(x) = arcsec<br />

233. f(x) = arccsc ( e 2x)<br />

8<br />

( 1<br />

[<br />

234. Show that arcsec(x) = arccos for |x| ≥1aslongasweuse 0,<br />

x)<br />

π ) ( π<br />

]<br />

∪<br />

2 2 ,π as the range<br />

of f(x) = arcsec(x).<br />

( 1<br />

235. Show that arccsc(x) =arcsin for |x| ≥1aslongasweuse<br />

[−<br />

x)<br />

π ) (<br />

2 , 0 ∪ 0, π ]<br />

as the range<br />

2<br />

of f(x) = arccsc(x).<br />

236. Show that arcsin(x) + arccos(x) = π for −1 ≤ x ≤ 1.<br />

2<br />

( 1<br />

237. Discuss with your classmates why arcsin ≠30<br />

2)<br />

◦ .<br />

238. Use the following picture and the series of exercises on the next page to show that<br />

arctan(1) + arctan(2) + arctan(3) = π<br />

y<br />

D(2, 3)<br />

A(0, 1)<br />

α β γ<br />

x<br />

O(0, 0) B(1, 0) C(2, 0)

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