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College Algebra, 2013a

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530 Hooked on Conics<br />

x 2<br />

) 2<br />

13.<br />

1 + 4 ( y − 1 2<br />

=1<br />

9<br />

Center ( 0, 1 )<br />

2<br />

Major Axis along x = 0 (the y-axis)<br />

Minor Axis along y = 1 2<br />

Vertices (0, 2), (0, −1)<br />

Endpoints of Minor Axis ( −1, 1 ( )<br />

2)<br />

, 1,<br />

1<br />

( ) ( )<br />

2<br />

Foci 0, 1+√ 5<br />

2<br />

, 0, 1−√ 5<br />

2<br />

e =<br />

15.<br />

17.<br />

√<br />

5<br />

3<br />

(x − 3) 2<br />

+<br />

9<br />

(y − 7)2<br />

25<br />

= 1 16.<br />

(x − 2) 2 (y +2)2<br />

14. + =1<br />

5 6<br />

Center (2, −2)<br />

Major Axis along x =2<br />

Minor Axis along y = −2<br />

Vertices ( 2, −2+ √ 6 ) ,(2, −2 − √ 6)<br />

Endpoints of Minor Axis ( 2 − √ 5, −2 ) ,<br />

( √ )<br />

2+ 5, −2<br />

Foci (2, −1), (2, −3)<br />

e =<br />

√<br />

6<br />

6<br />

x 2<br />

39 + y2<br />

64 =1<br />

x 2<br />

34 + y2<br />

25 = 1 18. (x − 8) 2 (y − 2)2<br />

+<br />

25 4<br />

(x − 5) 2 4(y − 2)2<br />

(x − 8) 2 (y +9)2<br />

19. + = 1 20. + =1<br />

25 75<br />

64 81<br />

21. Jamie and Jason should stand 100 − 25 √ 7 ≈ 33.86 feet from opposite ends of the gallery.<br />

22. Thearchcanbemodeledbythetophalfof x2<br />

9 + y2<br />

81<br />

= 1. One foot in from the base of the arch<br />

corresponds to either x = ±2. Plugging in x = ±2 givesy = ±3 √ 5 and since y represents a<br />

height, we choose y =3 √ 5 ≈ 6.71 feet.<br />

23. Distance from the sun to aphelion ≈ 1.0167 AU.<br />

Distance from the sun to perihelion ≈ 0.9833 AU.<br />

=1

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