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College Algebra, 2013a

College Algebra, 2013a

College Algebra, 2013a

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510 Hooked on Conics<br />

y 2 +4y +8x = 4<br />

y 2 +4y = −8x +4<br />

y 2 +4y +4 = −8x + 4 + 4 complete the square in y only<br />

(y +2) 2 = −8x +8 factor<br />

(y +2) 2 = −8(x − 1)<br />

Now that the equation is in the form given in Equation 7.3, we see that x − h is x − 1soh =1,and<br />

y − k is y +2sok = −2. Hence, the vertex is (1, −2). We also see that 4p = −8 sothatp = −2.<br />

Since p

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