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College Algebra, 2013a

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436 Exponential and Logarithmic Functions<br />

71. f(x) =3 x+2 − 4<br />

f −1 (x) =log 3 (x +4)− 2<br />

6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

y<br />

−4−3−2−1 1 2 3 4 5 6<br />

−1<br />

−2<br />

−3<br />

−4<br />

y = f(x) =3 x+2 − 4<br />

y = f −1 (x) =log 3 (x +4)− 2<br />

73. f(x) =−2 −x +1<br />

f −1 (x) =− log 2 (1 − x)<br />

x<br />

72. f(x) =log 4 (x − 1)<br />

f −1 (x) =4 x +1<br />

6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

y<br />

−2 −1 1 2 3 4 5 6<br />

−1<br />

−2<br />

y = f(x) =log 4 (x − 1)<br />

y = f −1 (x) =4 x +1<br />

74. f(x) = 5 log(x) − 2<br />

f −1 (x) =10 x+2<br />

5<br />

x<br />

2<br />

1<br />

y<br />

−2 −1 1 2<br />

−1<br />

−2<br />

y = f(x) =−2 −x +1<br />

y = f −1 (x) =− log 2 (1 − x)<br />

x<br />

5<br />

4<br />

3<br />

2<br />

1<br />

−4−3−2−1 1 2 3 4 5<br />

−1<br />

−2<br />

−3<br />

−4<br />

y = f(x) =5log(x) − 2<br />

y = f −1 (x) =10 x+2<br />

5<br />

y<br />

x<br />

75. (a) M(0.001) = log ( 0.001)<br />

= log(1) = 0.<br />

)<br />

(b) M(80, 000) = log = log(80, 000, 000) ≈ 7.9.<br />

(<br />

80,000<br />

0.001<br />

76. (a) L(10 −6 ) = 60 decibels.<br />

(b) I =10 −.5 ≈ 0.316 watts per square meter.<br />

(c) Since L(1) = 120 decibels and L(100) = 140 decibels, a sound with intensity level 140<br />

decibels has an intensity 100 times greater than a sound with intensity level 120 decibels.<br />

77. (a) The pH of pure water is 7.<br />

(b) If [H + ]=6.3 × 10 −13 then the solution has a pH of 12.2.<br />

(c) [H + ]=10 −0.7 ≈ .1995 moles per liter.

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