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College Algebra, 2013a

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6.1 Introduction to Exponential and Logarithmic Functions 419<br />

note that g(x) = ( 1<br />

2) x =<br />

(<br />

2<br />

−1 ) x =2 −x = f(−x), where f(x) =2 x . Thinking back to Section 1.7,<br />

the graph of f(−x) is obtained from the graph of f(x) by reflecting it across the y-axis. We get<br />

8<br />

7<br />

6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

y<br />

−3−2−1 1 2 3<br />

y = f(x) =2 x<br />

x<br />

reflect across y-axis<br />

−−−−−−−−−−−−→<br />

multiply each x-coordinate by −1<br />

8<br />

7<br />

6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

−3−2−1 1 2 3 x<br />

y = g(x) =2 −x = ( ) 1 x<br />

2<br />

We see that the domain and range of g match that of f, namely(−∞, ∞) and(0, ∞), respectively.<br />

Like f, g is also one-to-one. Whereas f is always increasing, g is always decreasing. As a result,<br />

as x →−∞, g(x) →∞, and on the flip side, as x →∞, g(x) → 0 + . It shouldn’t be too surprising<br />

that for all choices of the base 0

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