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College Algebra, 2013a

College Algebra, 2013a

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2.2 Absolute Value Functions 177<br />

By projecting the graph to the x-axis, we see that the domain is (−∞, ∞). Projecting to<br />

the y-axisgivesustherange[0, ∞). The function is increasing on [0, ∞) and decreasing on<br />

(−∞, 0]. The relative minimum value of f is the same as the absolute minimum, namely 0<br />

which occurs at (0, 0). There is no relative maximum value of f. There is also no absolute<br />

maximum value of f, sincethey values on the graph extend infinitely upwards.<br />

2. To find the zeros of g, we set g(x) =|x − 3| =0. ByTheorem2.1, wegetx − 3=0so<br />

that x = 3. Hence, the x-intercept is (3, 0). To find our y-intercept, we set x =0sothat<br />

y = g(0) = |0 − 3| = 3, which yields (0, 3) as our y-intercept. To graph g(x) =|x − 3|, weuse<br />

Definition 2.4 to rewrite g as<br />

g(x) =|x − 3| =<br />

{<br />

−(x − 3), if (x − 3) < 0<br />

(x − 3), if (x − 3) ≥ 0<br />

Simplifying, we get<br />

g(x) =<br />

{<br />

−x +3, if x

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