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College Algebra, 2013a

College Algebra, 2013a

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96 Relations and Functions<br />

1.<br />

f(x) =<br />

f(−x) =<br />

f(−x) =<br />

f(−x) = f(x)<br />

5<br />

2 − x 2<br />

5<br />

2 − (−x) 2<br />

5<br />

2 − x 2<br />

Hence, f is even. The graphing calculator furnishes the following.<br />

This suggests 4 that the graph of f is symmetric about the y-axis, as expected.<br />

2.<br />

g(x) =<br />

5x<br />

2 − x 2<br />

g(−x) =<br />

5(−x)<br />

2 − (−x) 2<br />

g(−x) = −5x<br />

2 − x 2<br />

It doesn’t appear that g(−x) is equivalent to g(x). To prove this, we check with an x value.<br />

After some trial and error, we see that g(1) = 5 whereas g(−1) = −5. This proves that g is<br />

not even, but it doesn’t rule out the possibility that g is odd. (Why not?) To check if g is<br />

odd, we compare g(−x) with−g(x)<br />

Hence, g is odd. Graphically,<br />

4 ‘Suggests’ is about the extent of what it can do.<br />

−g(x) = − 5x<br />

2 − x 2<br />

= −5x<br />

2 − x 2<br />

−g(x) = g(−x)

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