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College Algebra & Trigonometry, 2018a

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58 CHAPTER 1. ALGEBRA REVIEW<br />

The same is true for dividing fractions:<br />

1<br />

3 ÷ 2 ( 1<br />

)<br />

5 = (<br />

3<br />

2<br />

5).<br />

( 1<br />

We can take the complex fraction ( 3)<br />

2<br />

and multiply it by 1 without changing its<br />

5)<br />

value:<br />

1<br />

3 ÷ 2 ( 1<br />

)<br />

5 = (<br />

3<br />

2<br />

∗ 1<br />

5)<br />

=<br />

( 1<br />

3)<br />

( 2<br />

5)<br />

We can multiply by any form of 1 we want to and not change the value of the<br />

result.<br />

( 1<br />

( 3)<br />

2<br />

∗ 1=<br />

5)<br />

( 1<br />

3)<br />

( 2<br />

5)<br />

( 1<br />

( 3)<br />

2<br />

∗<br />

5) 9 ( 1<br />

)<br />

9 = (<br />

3<br />

2<br />

5)<br />

( 1<br />

( 3)<br />

2<br />

) ∗ 12<br />

( 1<br />

)<br />

12 = (<br />

3<br />

2<br />

5<br />

5)<br />

With a carefully chosen form of 1, we can transform the division problem into a<br />

multiplication problem.

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