College Algebra & Trigonometry, 2018a

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11.2. THE LAW OF SINES: THE AMBIGUOUS CASE 483 With ∠C ≈ 88.8 ◦ : 40 sin 38 = c ◦ sin 88.8 ◦ 40 0.6157 ≈ c 0.9998 0.9998∗ 40 0.6157 ≈ c 65.0 ≈ c So, our two possible solutions would be: ∠A =38 ◦ a =40 ∠B ≈ 126.8 ◦ b =52 ∠C ≈ 15.2 ◦ c ≈ 17.0 OR ∠A =38 ◦ a =40 ∠B ≈ 53.2 ◦ b =52 ∠C ≈ 88.8 ◦ c ≈ 65.0 Example 3 Solve the triangle if: ∠B =73 ◦ , b =51, a =92 Round the angles and side lengths to the nearest 10 th . Using the Law of Sines, we can say that: sin 73 ◦ 51 = sin A 92
484 CHAPTER 11. THE LAW OF SINES THE LAW OF COSINES 0.9563 51 ≈ sin A 92 92∗ 0.9563 51 ≈ sin A 1.7251 ≈ sin A As we saw previously, no real-valued angle has a sine greater than 1. Therefore, no triangle is possible.
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College Algebra & Trigonometry
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c○2018 Richard W. Beveridge This
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4 CONTENTS 2.4 Solution of Rational
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6 CONTENTS 8.2 The Trigonometric Ra
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8 CONTENTS
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88 CHAPTER 2. POLYNOMIAL AND RATION
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College Algebra & Trigonometry, 2018a

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