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College Algebra & Trigonometry, 2018a

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466 CHAPTER 10. TRIGONOMETRIC IDENTITIES AND EQUATIONS<br />

10.4 More Trigonometric Equations<br />

When the solution to a trigonometric equation is one of the quadrantal angles<br />

(0 ◦ ,90 ◦ , 180 ◦ , 270 ◦ and so on), then determining all the solutions between 0 ◦ and<br />

360 ◦ can work a little differently. The calculator will return some of these values,<br />

but in some cases it may not. If we go back to the unit circle, we can see this more<br />

clearly:<br />

(cos 90 ◦ , sin 90 ◦ )<br />

(0, 1)<br />

(cos 180 ◦ , sin 180 ◦ )<br />

(−1, 0)<br />

(cos 0 ◦ , sin 0 ◦ )<br />

(1, 0)<br />

(0, −1)<br />

(cos 270 ◦ , sin 270 ◦ )<br />

In the diagram above we can see the sine and cosine for 0 ◦ ,90 ◦ , 180 ◦ , and 270 ◦ .<br />

Since tan θ = sin θ<br />

cos θ , then we can see that tan 0◦ =0, tan 90 ◦ is undefined, tan 180 ◦ =<br />

0 and tan 270 ◦ is also undefined.<br />

The real issue with the quadrantal angles is finding sin −1 (0), cos −1 (0) or tan −1 (0).<br />

The calculator returns values of:<br />

sin −1 (0) = 0 ◦<br />

cos −1 (0) = 90 ◦<br />

tan −1 (0) = 0 ◦<br />

In each case, there is another possibility than differs from the given angle by 180 ◦ ,<br />

so:

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