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Combinatorics Through Guided Discovery, 2004a

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24 1. What is <strong>Combinatorics</strong>?<br />

(vii) How many terms of the form x n−i y i will you have?<br />

(c) Explain how you have just proved your conjecture from Problem 53.<br />

The theorem you have proved is called the Binomial Theorem.<br />

Problem 55. What is ∑ 10<br />

i=1 (10 i<br />

)3 i ? (h)<br />

Problem 56. What is ( n 0 ) − (n 1 ) + (n 2 ) −···±(n )<br />

n<br />

if n is an integer bigger than<br />

0? (h)<br />

Problem 57. Explain why<br />

m∑ ( m<br />

i<br />

i=0<br />

)( ) n<br />

=<br />

k − i<br />

( ) m + n<br />

.<br />

k<br />

Find two different explanations. (h)<br />

⇒<br />

Problem 58. From the symmetry of the binomial coefficients, it is not too<br />

hard to see that when n is an odd number, the number of subsets of<br />

{1, 2,...,n} of odd size equals the number of subsets of {1, 2,...,n} of even<br />

size. Is it true that when n is even the number of subsets of {1, 2,...,n} of<br />

even size equals the number of subsets of odd size? Why or why not? (h)<br />

⇒<br />

Problem 59.<br />

calculus.) (h)<br />

What is ∑ n<br />

i=0 i(n )?<br />

i<br />

(Hint: think about how you might use<br />

Notice how the proof you gave of the binomial theorem was a counting argument.<br />

It is interesting that an apparently algebraic theorem that tells us how to<br />

expand a power of a binomial is proved by an argument that amounts to counting<br />

the individual terms of the expansion. Part of the reason that combinatorial<br />

mathematics turns out to be so useful is that counting arguments often underlie<br />

important results of algebra. As the algebra becomes more sophisticated, so do the<br />

families of objects we have to count, but nonetheless we can develop a great deal<br />

of algebra on the basis of counting.

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