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Combinatorics Through Guided Discovery, 2004a

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C.3. Applications to recurrences. 155<br />

◦ Problem 384. Consider the recurrence a n = na n−1 +n(n −1). Multiply both<br />

sides by xn<br />

n!<br />

, and sum from n =2to ∞. (Why do we sum from n =2to<br />

infinity instead of n =1or n =0?) Letting y = ∑ ∞<br />

i=0 a ix i , show that the<br />

left-hand side of the equation is y − a 0 − a 1 x. Express the right hand side in<br />

terms of y, x, and e x . Solve the resulting equation for y and use the result<br />

to get an equation for a n . (A finite summation is acceptable in your answer<br />

for a n .)<br />

⇒ ·<br />

Problem 385. The telephone company in a city has n subscribers. Assume<br />

a telephone call involves exactly two subscribers (that is, there are no calls to<br />

outside the network and no conference calls), and that the configuration of<br />

the telephone network is determined by which pairs of subscribers are talking.<br />

Notice that we may think of a configuration of the telephone network<br />

as a permutation whose cycle decomposition consists entirely of one-cycles<br />

and two-cycles, that is, we may think of a configuration as an involution in<br />

the symmetric group S n .<br />

(a) Give a recurrence for the number c n of configurations of the network.<br />

(Hint: Person n is either on the phone or not.)<br />

(b) What are c 0 and c 1 ?<br />

(c) What are c 2 through c 6 ?<br />

⇒ ·<br />

Problem 386. Recall that a derangement of [n] is a permutation of [n] that<br />

has no fixed points, or equivalently is a way to pass out n hats to their n<br />

different owners so that nobody gets the correct hat. Use d n to stand for<br />

the number of derangements of [n]. We can think of derangement of [n] as<br />

a list of 1 through n so that i is not in the ith place for any n. Thus in a<br />

derangement, some number k different from n is in position n. Consider<br />

two cases: either n is in position k or it is not. Notice that in the second case,<br />

if we erase position n and replace n by k, we get a derangement of [n − 1].<br />

Based on these two cases, find a recurrence for d n . What is d 1 ? What is d 2 ?<br />

What is d 0 ? What are d 3 through d 6 ?<br />

C.3.1<br />

Using calculus with exponential generating functions<br />

⇒ ·<br />

Problem 387.<br />

recurrence.<br />

Your recurrence in Problem 385 should be a second order<br />

(a) Assuming that the left hand side is c n and the right hand side involves<br />

c n−1 and c n−2 , decide on an appropriate power of x divided by an ap-

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