Combinatorics Through Guided Discovery, 2004a
Combinatorics Through Guided Discovery, 2004a
Combinatorics Through Guided Discovery, 2004a
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154 C. Exponential Generating Functions<br />
◦ Problem 379. What is the EGF for the sequence 0, 1, 2, 3,...? You may think<br />
of this as the EFG for the number of ways to select one element from an n<br />
element set. What is the EGF for the number of ways to select two elements<br />
from an n-element set?<br />
· Problem 380. What is the EGF for the sequence 1, 1,...,1,...? Notice that<br />
we may think of this as the EGF for the number of identity permutations<br />
on an n-element set, which is the same as the number of permutations of<br />
n elements that are products of 1-cycles, or as the EGF for the number of<br />
ways to select an n-element set (or, if you prefer, an empty set) from an n-<br />
element set. As you may have guessed, there are many other combinatorial<br />
interpretations we could give to this EGF.<br />
◦ Problem 381. What is the EGF for the number of ways to select n distinct<br />
elements from a one-element set? What is the EGF for the number of ways<br />
to select a positive number n of elements from a one element set? Hint:<br />
When you get the answer you will either say “of course,” or “this is a silly<br />
problem.” (h)<br />
· Problem 382. What is the EGF for the number of partitions of a k-element<br />
set into exactly one block? (Hint: is there a partition of the empty set into<br />
exactly one block?)<br />
· Problem 383. What is the EGF for the number of ways to arrange k books<br />
on one shelf (assuming they all fit)? What is the EGF for the number of<br />
ways to arrange k books on a fixed number n of shelves, assuming that all<br />
the books can fit on any one shelf? (Remember Problem 122.)<br />
C.3 Applications to recurrences.<br />
We saw that ordinary generating functions often play a role in solving recurrence<br />
relations. We found them most useful in the constant coefficient case. Exponential<br />
generating functions are useful in solving recurrence relations where the coefficients<br />
involve simple functions of n, because the n! in the denominator can cancel<br />
out factors of n in the numerator.