082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017
956 Chapter 29 Statistics and probability distributions29.10.3 MostlikelynumberofsuccessesWhen conducting a series of trials it is sometimes desirable to know the most likelyoutcome. For example, what is the most likely number of acceptable components in asample of five tested?Example29.19 Theprobabilityacomponentisacceptableis0.8.Fivecomponentsarepickedatrandom.What isthe mostlikely number of acceptable components?( 5Solution P(no acceptable components) = (0.8)0)0 (0.2) 5 = 3.2 ×10 −4( 5P(1 acceptable component) = (0.8)1)1 (0.2) 4 = 6.4 ×10 −3( 5P(2 acceptable components) = (0.8)2)2 (0.2) 3 = 0.0512( 5P(3 acceptable components) = (0.8)3)3 (0.2) 2 = 0.2048( 5P(4 acceptable components) = (0.8)4)4 (0.2) 1 = 0.4096( 5P(5 acceptable components) = (0.8)5)5 (0.2) 0 = 0.3277The mostlikely number of acceptable components isfour.Example 29.19 illustrates an important general result. Suppose we conductnBernoullitrialsandwishtofindthemostlikelynumberofsuccesses.Ifp =probabilityofsuccesson a single trial,andi =mostlikely number ofsuccesses inntrials,thenp(n+1)−1<i<p(n+1)InExample 29.19, p = 0.8,n = 5 and so(0.8)(6) −1 <i < (0.8)(6)3.8<i<4.8Sinceiisan integer, theni = 4.EXERCISES29.101 Theprobabilityacomponentisacceptableis0.8.Fourcomponents are sampled. What is the probability that(a) exactly one is acceptable(b) exactly two are acceptable?2 Amachine requires allseven ofitsmicro-chips tooperate correctly in order to be acceptable. Theprobability amicro-chip isoperating correctly is 0.99.(a) What isthe probability the machine isacceptable?(b) What isthe probability that sixofthe seven chipsare operating correctly?(c) Themachine is redesigned sothat the originalseven chips are replaced by four new chips.Theprobability a new chipoperates correctly is0.98.
29.11 The Poisson distribution 957Isthe new designmore orlessreliable than theoriginal?3 Theprobability a machine has a lifespanofmore than5 years is0.8. Ten machines are chosen atrandom.What isthe probability that(a) eightmachines have a lifespanofmore than 5years(b) allmachines have alifespan ofmore than 5 years(c) atleast eight machines have alifespanofmorethan5years(d) nomore than two machines have alifespanoflessthan 5 years?4 Theprobability a valve remainsreliable formore than10years is 0.75.Eightvalves are sampled. What isthe most likely number ofvalvesto remain reliableformore than 10years?5 The probability a chipis manufactured to anacceptable standard is 0.87.Asampleofsixchipsispicked at random from a large batch.(a) Calculate the probability all sixchipsareacceptable.(b) Calculate the probability none ofthe chipsisacceptable.(c) Calculate the probability that fewer than fivechips in the sampleare acceptable.(d) Calculate the mostlikely number ofacceptablechips in the sample.(e) Calculate the probability that more than twochips are unacceptable.Solutions1 (a) 0.0256 (b) 0.15362 (a) 0.9321 (b) 0.0659 (c) 0.9224.New designis lessreliable3 (a) 0.3020 (b) 0.1074 (c) 0.678 (d) 0.6784 65 (a) 0.4336 (b) 4.826 ×10 −6 (c) 0.1776 (d) 6(e) 0.032429.11 THEPOISSONDISTRIBUTIONThePoissondistributionmodelsthenumberofoccurrencesofaneventinagiveninterval.Consider the number of emergency calls received by a service engineer in one day.Wemayknowfromexperiencethatthenumberofcallsisusuallythreeorfourperday,butoccasionallyitwillbeonlyoneortwo,orevennone,andonsomedaysitmaybesixor seven, or even more. This example suggests a need for assigning a probability to thenumberofoccurrencesofaneventduringagiventimeperiod.ThePoissondistributionserves this purpose.Thenumberofoccurrencesofanevent,E,inagiventimeperiodisadiscreterandomvariable which we denote by X. We wish to find the probability that X = 0, X = 1,X = 2, X = 3, and so on. Suppose the occurrence of E in any time interval is notaffectedbyitsoccurrenceinanyprecedingtimeinterval.Forexample,acarisnotmore,or less, likely to pass a given spot in the next 10 seconds because a car passed (or didnotpass) the spot inthe previous 10 seconds, thatisthe occurrences areindependent.Let λ be the expected (mean) value ofX, the number of occurrences during the timeperiod. IfX is measured for many time periods the average value ofX will be λ. UnderthegivenconditionsX followsaPoissondistribution.TheprobabilitythatX hasavaluer isgiven byP(X=r)= e−λ λ rr!r=0,1,2,...
- Page 925 and 926: 28.2 Introducing probability 905Ifm
- Page 927 and 928: 28.2 Introducing probability 907Eng
- Page 929 and 930: 28.3 Mutually exclusive events: the
- Page 931 and 932: 28.3 Mutually exclusive events: the
- Page 933 and 934: 28.4 Complementary events 913EXERCI
- Page 935 and 936: 28.5 Concepts from communication th
- Page 937 and 938: 28.5 Concepts from communication th
- Page 939 and 940: 28.6 Conditional probability: the m
- Page 941 and 942: 28.6 Conditional probability: the m
- Page 943 and 944: P(A ∩C) =P(C ∩A) =P(C)P(A|C)P(A
- Page 945 and 946: 28.7 Independent events 9255 Compon
- Page 947 and 948: 28.7 Independent events 927Solution
- Page 949 and 950: 28.7 Independent events 929E 1,E 2a
- Page 951 and 952: Review exercises 28 931(d) A compon
- Page 953 and 954: 29 Statisticsandprobabilitydistribu
- Page 955 and 956: 29.3 Probability distributions -- d
- Page 957 and 958: 29.4 Probability density functions
- Page 959 and 960: 29.5 Mean value 939Example29.3 Find
- Page 961 and 962: 29.6 Standard deviation 94129.6 STA
- Page 963 and 964: 29.7 Expected value of a random var
- Page 965 and 966: 29.7 Expected value of a random var
- Page 967 and 968: 29.8 Standard deviation of a random
- Page 969 and 970: 29.9 Permutations and combinations
- Page 971 and 972: 29.9 Permutations and combinations
- Page 973 and 974: 29.10 The binomial distribution 953
- Page 975: 29.10 The binomial distribution 955
- Page 979 and 980: Table29.6Theprobabilitiesforbinomia
- Page 981 and 982: 29.12 The uniform distribution 9615
- Page 983 and 984: 29.14 The normal distribution 963So
- Page 985 and 986: 29.14 The normal distribution 965N(
- Page 987 and 988: 29.14 The normal distribution 967Ta
- Page 989 and 990: 29.14 The normal distribution 969EX
- Page 991 and 992: 29.15 Reliability engineering 971in
- Page 993 and 994: 29.15 Reliability engineering 973En
- Page 995 and 996: 29.15 Reliability engineering 975k
- Page 997 and 998: Review exercises 29 977Solutions1 0
- Page 999 and 1000: AppendicesContents I Representingac
- Page 1001 and 1002: II The Greek alphabet 981f(t)T0 t 0
- Page 1003 and 1004: Indexabsolute quantity88absorption
- Page 1005 and 1006: Index 985chord 357--8circuital law
- Page 1007 and 1008: Index 987cycle ofsint 131cycles ofl
- Page 1009 and 1010: Index 989eigenvalues andeigenvector
- Page 1011 and 1012: Index 991spectra 766--8t-w duality
- Page 1013 and 1014: Index 993characteristic impedance o
- Page 1015 and 1016: Index 995exclusive OR gate 189NAND
- Page 1017 and 1018: Index 997second-order 829--30, 833,
- Page 1019 and 1020: Index 999remainder term,Taylor’s
- Page 1021 and 1022: Index 1001solenoidal vectorfield 85
- Page 1023 and 1024: Index 1003calculus 849--66curl859--
956 Chapter 29 Statistics and probability distributions
29.10.3 Mostlikelynumberofsuccesses
When conducting a series of trials it is sometimes desirable to know the most likely
outcome. For example, what is the most likely number of acceptable components in a
sample of five tested?
Example29.19 Theprobabilityacomponentisacceptableis0.8.Fivecomponentsarepickedatrandom.
What isthe mostlikely number of acceptable components?
( 5
Solution P(no acceptable components) = (0.8)
0)
0 (0.2) 5 = 3.2 ×10 −4
( 5
P(1 acceptable component) = (0.8)
1)
1 (0.2) 4 = 6.4 ×10 −3
( 5
P(2 acceptable components) = (0.8)
2)
2 (0.2) 3 = 0.0512
( 5
P(3 acceptable components) = (0.8)
3)
3 (0.2) 2 = 0.2048
( 5
P(4 acceptable components) = (0.8)
4)
4 (0.2) 1 = 0.4096
( 5
P(5 acceptable components) = (0.8)
5)
5 (0.2) 0 = 0.3277
The mostlikely number of acceptable components isfour.
Example 29.19 illustrates an important general result. Suppose we conductnBernoulli
trialsandwishtofindthemostlikelynumberofsuccesses.Ifp =probabilityofsuccess
on a single trial,andi =mostlikely number ofsuccesses inntrials,then
p(n+1)−1<i<p(n+1)
InExample 29.19, p = 0.8,n = 5 and so
(0.8)(6) −1 <i < (0.8)(6)
3.8<i<4.8
Sinceiisan integer, theni = 4.
EXERCISES29.10
1 Theprobabilityacomponentisacceptableis0.8.Four
components are sampled. What is the probability that
(a) exactly one is acceptable
(b) exactly two are acceptable?
2 Amachine requires allseven ofitsmicro-chips to
operate correctly in order to be acceptable. The
probability amicro-chip isoperating correctly is 0.99.
(a) What isthe probability the machine is
acceptable?
(b) What isthe probability that sixofthe seven chips
are operating correctly?
(c) Themachine is redesigned sothat the original
seven chips are replaced by four new chips.The
probability a new chipoperates correctly is0.98.