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Equation3

Review exercises 26 865

curlE=∇×E=− ∂B

∂t

where E is the electric field strength. This equation is a statement of Faraday’s law. A

time-varying magnetic field produces a space-varying electric field.

Equation4

curlH=∇×H=J+ ∂D

∂t

where H is the magnetic field strength and J is the free current density. This equation

statesthatatime-varying electric field gives risetoaspace-varying magnetic field.

The derivation of these equations is beyond the scope of this text but can be found in

manybooksonelectromagnetism.Thepoweroftheseequationsliesintheirgenerality.

Thebrevitywithwhichthemainlawsofelectromagnetismcanbeexpressedisatribute

tothe utility ofvector calculus.

REVIEWEXERCISES26

1 Find ∇φif

(a) φ = 3xyz

(b) φ =x 2 yz+xy 2 z+xyz 2

(c) φ =xy 2 z 2 +x 2 yz 2 +x 2 y 2 z

2 Ifφ=1/ √ x 2 +y 2 +z 2 ,showthat

∂ 2 φ

∂x 2 + ∂2 φ

∂y 2 + ∂2 φ

∂z 2 = 0

3 Functions satisfyingLaplace’sequationare called

harmonicfunctions.Showthat the following

functionsare harmonic:

(a) z =x 4 −6x 2 y 2 +y 4

(b) z = 4x 3 y −4xy 3

4 IfA=xi+yj+zkand

B = cosxi −sinxj,find

(a) A×B

(b) ∇·(A×B)

(c) ∇×A

(d) ∇×B

Verifythat

∇·(A×B)=B·(∇×A)−A·(∇×B).

5 Forarbitrary differentiablescalar fields φ and ψ show

that∇(φψ) = ψ∇φ +φ∇ψ.

6 Ifψ=x 2 yanda=xi+yj+zk,find∇ψ,

∇ ×a,∇ × (ψa).Showthat

∇×(ψa)=ψ∇×a+(∇ψ)×a.

7 Ascalarfield φ isafunctionofx,zandt only.Vectors

E and Hare defined by

( )

E = 1 ∂φ

ε ∂z i − ∂φ

∂x k H = − ∂φ

∂t j

where ε isaconstant.

(a) Show that ∇ ·E = 0.

(b) Show that ∇ ·H = 0.

Given that ∇ ×E = −µ ∂H ,where µ isaconstant,

∂t

show that φ satisfiesthe partial differential equation

∂ 2 φ

∂x 2 + ∂2 φ

∂z 2 = φ

µε∂2 ∂t 2

8 Ifv = (2x 2 y+3x 5 )i+e xy j+xyzkfind ∂v

∂x and ∂2 v

∂x 2.

9 An electrostatic potential isgiven byV = 5xyz.Find

(a) the associatedelectric field E,

(b) |E| atthe point (1,1,1).

10 An electrostatic field is given by

E = 3(x+y)i+2xyj.Findthedirectionofthisfieldat

(a) the point (2,2)

(b) the point (3,4).

11 Find the curlofA =yi +2xyj +3zk.

12 Find the curlofthe vector field

F = (x 2 −y)i + (xy −4y 2 )j.

13 If φ = 5e x+2y coszfind ∇φ atthepoint (0,0,0).

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