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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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68 Chapter 2 Engineering functions

EXERCISES2.3

1 Representthe followingintervals onthe real line:

(a) [1,3] (b) [2,4)

(c) (0,3.5) (d) [−2,0)

(e) (−1,1] (f) 2x<4

(g) 0<x<2 (h) −3x −1

(i) 0x<3

2 Describe the rule associated with the following

functions,sketch their graphs and state their domains

and ranges:

(a) f(x) =2x 2

(b)f(x)=x 2 −1

(c)g(t)=3t−4

(d)y(x) =x 3

0x

0t

(e)f(t)=0.5t+2 −2t10

(f)z(x)=3x−2

3 Iff(x)=5x+4,find

(a) f(3)

(b) f(−3)

(c) f(α)

(d) f(x+1)

(e) f(3α)

(f) f(x 2 )

4 Ifg(t) =5t 2 −4,find

(a) g(0)

(b) g(2)

(c) g(−3)

(d) g(x)

(e) g(2t −1)

3x8

5 Thereactance,X C ,offered by acapacitor is given by

X C = 1 ,where f isthe frequency ofthe applied

2πfC

alternating current, andC is the capacitance ofthe

capacitor. IfC = 10 −6 F,findX C when f = 50 Hz.

6 Classifythe functions in Question2asone-to-oneor

many-to-one.

7 Find the inverse ofthe followingfunctions:

(a) f(x)=x+4

(b) g(t) =3t +1

(c) y(x) =x 3

(d) h(t) = t −8

3

(e) f(t) = t −1

3

(f) h(x) =x 3 −1

(g) k(v)=7−v

(h) m(n) = 3 1 (1 −2n)

8 Givenf(t) =2t,g(t) =t −1andh(t) =t 2 write

expressions for

(a) f(g(t)) (b) f(h(t))

(c) g(h(t)) (d) g(f(t))

(e) h(g(t)) (f) h(f(t))

(g) f(f(t)) (h) g(g(t))

(i) h(h(t)) (j) f(g(h(t)))

(k) g(f(h(t))) (l) h(g(f(t)))

9 Givenf(t) =t 2 +1,g(t) =3t +2andh(t) = 1 t ,

write expressions for

(a) f(g(t)) (b) f(h(t))

(c) g(h(t)) (d) h(f(t))

(e) f(g(h(t)))

10 Given f(t) =2t,g(t) =2t +1,h(t) =1−3t,write

expressions forthe following:

(a) f −1 (t) (b)g −1 (t) (c)h −1 (t)

11 Givena(x) = 3x −2,b(x) = 2 x ,c(x)=1+1 x write

expressions for

(a)a −1 (x) (b)b −1 (x) (c)c −1 (x)

12 Givenf(t) =2t +3,g(t) =3tandh(t) = f(g(t))

write expressions for

(a) h(t)

(b) f −1 (t)

(c) g −1 (t)

(d) h −1 (t)

(e) g −1 (f −1 (t))

Whatdoyou noticeabout(d)and(e)?

13 Sketch the following functions:

{

t 0t3

(a) f(t) =

3 3<t4

{

2 −x 0x<1

(b) g(x) =

2 1x3

{

1 −t 0t1

(c) a(t) =

t−1 1<t2

⎪⎨

2 0 x1

(d) b(x) = 1 1<x2

⎪⎩

3−x 2<x3

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