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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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Review exercises 23 755

The values of the first few coefficients are

b 1

= 2 π (1−cosπ)= 4 π

b 2

= 2

2π (1−cos2π)=0

b 3

= 2 4

(1 −cos3π) =

3π 3π

The next stage is toevaluate the gain and phase changes of the Fourier components.

Using Equations (23.13) and (23.14):

n = 1

ω 1

=1

|G(jω 1

)| =

1

1+0.09×1

= 0.96

n = 3

n = 5

G(jω 1

) = −tan −1 0.3 = −16.7 ◦

ω 3

=3

|G(jω 3

)| =

1

1+0.09×9

= 0.74

G(jω 3

) = −tan −1 0.9 = −42.0 ◦

ω 5

=5

|G(jω 5

)| =

1

1+0.09×25

= 0.55

G(jω 5

) = −tan −1 1.5 = −56.3 ◦

It is clear that high-frequency Fourier components are attenuated and phase shifted

more than low-frequency Fourier components. The effect is to produce a rounding

of the rising and falling edges of the square wave input signal. This is illustrated

in Figure 23.29(b). The output signal has been obtained by adding together the

attenuated and phase-shifted output Fourier components. This is possible because

the systemislinear.

REVIEWEXERCISES23

1 Find the half-range Fourier sineseries representation

off(t)=tsint,0tπ.

2 Find the half-range sineseries representationof

f(t)=cos2t,0tπ.

3 Find (a) the half-range sineseries,and(b)the

half-rangecosine seriesrepresentation ofthe function

defined in the interval [0, τ]by

4t

⎪⎨ τ

f(t)= ( )

4

⎪⎩ 1 − t 3 τ

0t τ 4

τ

4 tτ

4 Find the Fourier series representation ofthe function

with periodT defined by

{

V(constant) |t| <T/6

f(t)=

0 T/6|t|T/2

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