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23.9 Frequency response of a linear system 751

The observant reader will note that the expressions forc n

appear invalid whenn = 0,

since the denominator is then zero. We can computec 0

in either of two ways. Using an

integral expression we see that

c 0

= 1 T

∫ T/4

−T/41dt = 1 2

Also,using a Taylor series expansion itispossible toshow

[ ]

1 e

−j2nπt/T T/4

lim

= 1

n→0T

−j2nπ/T

−T/4

2

giving a consistentresult.

EXERCISES23.8

1 Find the complex Fourier seriesrepresentation of

(a) f(t) =

{

1 0 <t<2

0 2<t<4

period 4

(b) f(t)=e t −1<t<1 period2

{

Asinωt 0<t <π/ω

(c) f(t) =

0 π/ω<t<2π/ω

period 2π/ω

2 If

∞∑

f(t)= c n e j2nπt/T

−∞

show thatthe coefficients,c n ,are given by

c n = 1 ∫ T

f (t)e −j2nπt/T dt

T 0

[Hint: multiply both sidesbye −j2mπt/T and integrate

over [0,T].]

Solutions

1 (a)

(b)

∞∑ j

(cosnπ −1)ejnπt/2

2nπ

−∞

(

)

1

∞∑ e −jnπ+1 −e −1+jnπ

e jnπt

2 1−jnπ

−∞

(c)

∞∑ A(1 +e −jnπ )e jnωt

2π(1 −n

−∞

2 )

23.9 FREQUENCYRESPONSEOFALINEARSYSTEM

Linear systems have the property that the response to several inputs being applied to

thesystemcanbeobtainedbyaddingtheeffectsoftheindividualinputs.Anotheruseful

property of linear systems is that if a sinusoidal input is applied to the system then the

output will also be a sinusoid of the same frequency but with modified amplitude and

phase.This isillustratedinFigure 23.26.

InSection9.7wesawthatsinusoidalsignalscanberepresentedbycomplexnumbers

and that an a.c. electrical circuit can be analysed using complex numbers. This is true

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