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22.11 Inversion of z transforms 715

EXERCISES22.10

1 UseTable 22.2 to find theztransformsof

(a)3(4) k +7k 2 ,k 0

(b)3e −k sin4k−k,k 0

2 Find theztransformsofthe following continuous

functionssampledatt =kT,k ∈ N:

(a) t 2 (b) 4t (c) sin2t

(d) u(t −4T )

(e) e 3t

3 Find theztransformof (k −3)u[k −3]bydirectuse

ofthe definition oftheztransform.Hence verifythe

resultofExample 22.24.

4 Provethat theztransformofe −at f (t)isF(e aT z).

5 Prove the firstandsecond shifttheorems.

6 Use the complex translation theoremto findthez

transformsof

(a) ke −bk

(b) e −k sink

7 If f[k] = 4(3) k find Z{f[k]}.Usethefirstshift

theorem to deduce Z{f[k +1]}.Show that

Z{f[k+1]}−3Z{f[k]}=0.

8 Write down the firstfive terms ofthe sequence

definedby f[k] = 4(2) k−1 u[k −1],k 0.Finditsz

transformdirectly, andalso byusingthe second shift

theorem.

Solutions

1 (a)

(b)

2 (a)

(c)

(e)

3z 7z(z +1)

1

+

z −4 (z −1) 3

3

z 2 (z −1) 2

3ze −1 sin4

z 2 −2ze −1 cos4 +e −2 − z

ze b

(z −1) 2 6 (a)

(ze b −1) 2

T 2 z(z +1) 4Tz

ezsin1

(z −1) 3 (b)

(z −1) 2 (b)

e 2 z 2 −2ezcos1+1

zsin2T 1

z 2 (d)

4z

−2zcos2T +1 z 3 (z−1) 7

z −3 , 12z

z −3

z

z−e 3T 8 0, 4,8,16,32.

4

z −2

22.11 INVERSIONOFzTRANSFORMS

Just as it is necessary to invert Laplace transforms we need to be able to invertztransforms

and as before we can make use of tables of transforms, partial fractions and the

shift theorems.Invery complicatedcasesmore advanced techniquesarerequired.

Example22.26 IfF(z) = z +3 ,find f[k].

z −2

Solution Note that wecan writeF(z)as

z +3

z −2 = z

z −2 + 3

z −2

Thereasonforthischoiceisthatquantitieslikethefirstonther.h.s.appearinTable22.2.

Fromthis table we find

Z{2 k } = z

z −2

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