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21.11 Transfer functions 663

R(s) +

X 2 (s)

G(s)

Y(s)

X 1 (s)

H(s)

R(s)

G(s)

1 + G(s)H(s)

Y(s)

Figure21.7

Block diagram foranegative feedback loop.

Figure21.8

Simplifiedblock diagram foranegative

feedback loop.

The simplified block diagram for a negative feedback loop isshown inFigure 21.8.

A complicated engineering system may be represented by many differential equations.

The output from one part of the system may form the input to another part. Consider

the following example.

Example21.29 Asystemismodelled bythe differential equations

x ′ +2x=f(t) (21.10)

2y ′ −y =x(t) (21.11)

In Equation (21.10) the input is f (t) and the output is x(t). In Equation (21.11), x(t)

is the input andy(t) is the final output of the system. Find the overall system transfer

functionassumingzero initial conditions.

Solution The output from Equation (21.10) isx(t); this forms the input to Equation (21.11). The

blockdiagramsforEquations(21.10)and(21.11)arecombinedintoasingleblockdiagramasshown

inFigure 21.9.

UsingRule 1,the overall systemtransferfunction can thenbefound:

G(s) = Y(s)

F(s) = 1

(s +2)(2s −1)

This transferfunction relatesY(s)andF(s)(see Figure 21.10).

F(s)

1

X(s)

1

Y(s)

s + 2

2s – 1

F(s)

1

(s + 2)(2s – 1)

Y(s)

Figure21.9

Combinedblock diagram for

Equations(21.10)and (21.11).

Figure21.10

Theoverall systemtransfer function.

Example21.30 Asystemisrepresentedby the differential equations

2x ′ −x=f(t)

y ′ +3y =x(t)

z ′ +z=y(t)

The initial input is f (t) and the final output is z(t). Find the overall system transfer

function, assumingzeroinitial conditions.

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