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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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1.8 Summation notation 47

Engineeringapplication1.8

Kirchhoff’scurrentlaw

Kirchhoff’scurrentlaw,oftenabbreviatedtoKCL,providesoneofthefundamental

equationsforanalysingelectricalcircuits.Thelawstatesthatthesumofthecurrents

flowing out of any junction, or node, in a circuit must equal the sum of the currents

flowing into it.

This principle is intuitive as it has a direct analogy with fluid flow in connected

water pipes. Currents flowing into a junction are considered positive; those flowing

out of a junction are negative. It is then valid to say that the sum of the currents

at a junction is zero. If there are N currents at the junction, denoted I 1

,I 2

,...,I N

,

then

I 1

+I 2

+I 3

+···+I N−1

+I N

=0

This can be expressed using the summation notation as

N∑

I k

=0

k=1

HereI k

means ‘the current,I, in branchk’. The first equation can be produced from

the summation notation by first substitutingk = 1, thenk = 2, right up tok = N.

Theexpressionbelowthesummationsymboltellsyouwheretostartandthevariable

to be substituted, and the number above the summation symbol indicates where to

stopcounting.Summationnotationisaverycompactandprecisewayofexpressing

KCL forany number ofcurrents atanode.

Consider the node shown inFigure 1.5.

Branch 1 Branch 3

1 A

2 A

3 A 2 A Figure1.5

Acircuit node with four separate branches.The currents are

Branch 2 Branch 4 given in amperes(oramps,A).

It can be seen that the total current flowing into the node is 1 + 3 = 4 amps. The

current flowing outof the node is2 +2 = 4 amps. Clearly,

Total current flowing into node =total currentflowing outof node

Alternatively, using the summation formof KCL wehave

4∑

I k

=I 1

+I 2

+I 3

+I 4

=0=1+3−2−2

k=1

Notethatforcurrentsflowingoutofthenodeanegativesignisusedandforcurrents

flowing into the node a positive sign is used. This is equivalent to considering the

currents separately as inward and outward flowing currents and equating the two.

Suppose for a moment that we did not know the current in branch 4 and,

furthermore, itwas notlabelled with anarrow toshow the direction of current flow.

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