25.08.2021 Views

082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

19.6 Constant coefficient equations 577

For many transmission lines of interest the signal that is being carried varies sinusoidally

with time. Therefore the voltage and current depend on both position along

theline,z,andtime,t.However,itiscommontoseparatethetimedependencefrom

the voltage and current expressions in order to simplify the analysis. It must be remembered

that any voltage and current variation with position has superimposed

uponitasinusoidalvariationwithtime.Therefore,ignoringthetime-dependentelement

we write the voltage as v and the current asi, knowing that they are functions

ofz.

y

i

i + di

di

Cdz

y L

Ldz

Gdz

y R

Rdz

y + dy

i C

iG

z

dz

Figure19.9

A section ofatransmissionline.

ConsiderthecircuitofFigure19.9whichrepresentsasectionofthetransmission

line oflength δz. Applying Kirchhoff’s voltage law tothe circuityields

v+δv−v+v L

+v R

=0

δv=−v L

−v R

where v L

is the voltage across the inductor and v R

is the voltage across the resistor.

Using the individual component laws for the inductor and resistorgives

δv = −ijωLδz −iRδz

= −i(R +jωL)δz

Notethat δihasbeenignoredbecauseitissmallcomparedtoi.Nowconsidertheparallelcombinationofthecapacitorandresistor(withunitsofconductance).Applying

Kirchhoff’s current law tothiscombination yields

δi=i C

+i G

wherei C

isthecurrentthroughthecapacitorandi G

isthecurrentthroughtheresistor.

Using the individual component laws for the capacitor and resistor gives

δi = −vjωCδz − vGδz

= −v(G +jωC)δz

Dividing these two circuitequations by δzyields

δv

δz

= −i(R +jωL)

δi

δz = −v(G+jωC)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!