082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017
494 Chapter 16 Further topics in integrationREVIEWEXERCISES161 Show f (x) =x n andg(x) =x m areorthogonalon[−k,k] ifn +mis an odd number.2 Show f (t) = sint andg(t) = cost are orthogonal on[a,a +nπ].3 Show f (t) = sinht andg(t) = cosht are orthogonalover [−k,k].4 Determine the values ofkforwhich ∫ ∞0 t k dt exists.5 Evaluate ifpossible∫ ∞(a) u(t)dt∫0∞(b) e −1000t dt−∞∫ 0 1(c)−2 x +1 dx∫ ∞(d) u(t)e −t dt−∞∫ 2 1(e)−2 x 2 −1 dx(Note thatu(t)is the unitstepfunction.)6 Find the values ofkforwhich ∫ ∞0 e kt dt exists.7 Evaluate∫ ∞(a) (t 2 +1)δ(t −1)dt−∞∫ ∞(b) te t δ(t −2)dt−∞∫ ∞(c) (t 2 +t +2)δ(t −1)dt−∞∫ ∞ δ(t +2)(d)−∞ t 2 +1 dt∫ ∞(e) δ(t +1)δ(t +2)dt−∞8 (a) Evaluate∫ ∞(t 2 +1)δ(2t)dt−∞[Hint: substitutez = 2t.](b) Show∫ ∞f(t)δ(nt)dt = 1 f(0), n>0−∞ n9 Evaluate∫ ∞(a) (1+t)δ(t −2)dt0∫ ∞(b) tδ(1+t)dt−∞∫ ∞(c) (1+t)δ(−t)dt−∞∫ 0(d) δ(t−6)+δ(t+6)dt−∞∫ 4k(e) δ(t +k)+δ(t +3k)+δ(t +5k)dt−2kk > 010 Thefunctiong(t)ispiecewise continuous anddefined by{ 2t 0t1g(t) =3 1<t2Evaluate∫ 1(a) g(t)dt0∫ 1.5(b) g(t)dt0∫ 1.7(c) g(t)dt0.5∫ 2(d) g(t)dt1∫ 1.5(e) g(t)dt1.311 Given⎧⎨1+t −1t<3f(t)= t−1 3t4⎩0 otherwiseevaluate∫ 2(a) f(t)dt−1∫ 4(b) f(t)dt−1∫ 5(c) f(t)dt0∫ ∞(d) f(t)δ(t −2)dt−∞∫ ∞(e) f(t)u(t)dt−∞
Review exercises 16 49512 Given14 Given⎧⎨t 2 v(t) =2ti+(3−t 2 )j+t 3 k−2t2h(t) = t⎩3 find2<t3∫ 14 3<t5(a) vdt0evaluate∫∫ 22(b) vdt(a) h(t)dt1−1∫∫ 22.5(c) vdt(b) h(t)dt00∫ 415 Evaluate the following integrals:(c) h(t)+1dt∫23∫ 4(a) |t|dt−1(d) h(t +1)dt∫02∫ 2(b) |t+2|dt−3(e) h(2t)dt∫−1213 Ifa =ti−2tj+3tk,find ∫ 10 adt. (c) |3t −1|dt0Solutions4 k<−15 (a) does notexist(b) does notexist(c) does notexist(d) 1(e) does notexist6 k<07 (a) 2 (b) 14.7781 (c) 4(d) 0.2 (e) 08 (a) 1 29 (a) 3 (b) −1 (c) 1(d) 1 (e) 1510 (a) 1 (b)2(d) 3 (e) 0.6(c) 2.8511 (a) 4.5 (b) 10.5 (c) 10(d) 3 (e) 1012 (a) 3(b) 8.4323(c) 22.25(d) 26.5833(e) 12.791713 0.5i −j+1.5k14 (a) i+ 8 3 j + 1 4 k(b) 3i + 2 3 j + 154 k(c) 4i + 103 j+4k15 (a) 5 (b) 8.5 (c)133
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- Page 555 and 556: 19.2 Basic definitions 535In engine
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494 Chapter 16 Further topics in integration
REVIEWEXERCISES16
1 Show f (x) =x n andg(x) =x m areorthogonalon
[−k,k] ifn +mis an odd number.
2 Show f (t) = sint andg(t) = cost are orthogonal on
[a,a +nπ].
3 Show f (t) = sinht andg(t) = cosht are orthogonal
over [−k,k].
4 Determine the values ofkforwhich ∫ ∞
0 t k dt exists.
5 Evaluate ifpossible
∫ ∞
(a) u(t)dt
∫0
∞
(b) e −1000t dt
−∞
∫ 0 1
(c)
−2 x +1 dx
∫ ∞
(d) u(t)e −t dt
−∞
∫ 2 1
(e)
−2 x 2 −1 dx
(Note thatu(t)is the unitstepfunction.)
6 Find the values ofkforwhich ∫ ∞
0 e kt dt exists.
7 Evaluate
∫ ∞
(a) (t 2 +1)δ(t −1)dt
−∞
∫ ∞
(b) te t δ(t −2)dt
−∞
∫ ∞
(c) (t 2 +t +2)δ(t −1)dt
−∞
∫ ∞ δ(t +2)
(d)
−∞ t 2 +1 dt
∫ ∞
(e) δ(t +1)δ(t +2)dt
−∞
8 (a) Evaluate
∫ ∞
(t 2 +1)δ(2t)dt
−∞
[Hint: substitutez = 2t.]
(b) Show
∫ ∞
f(t)δ(nt)dt = 1 f(0), n>0
−∞ n
9 Evaluate
∫ ∞
(a) (1+t)δ(t −2)dt
0
∫ ∞
(b) tδ(1+t)dt
−∞
∫ ∞
(c) (1+t)δ(−t)dt
−∞
∫ 0
(d) δ(t−6)+δ(t+6)dt
−∞
∫ 4k
(e) δ(t +k)+δ(t +3k)+δ(t +5k)dt
−2k
k > 0
10 Thefunctiong(t)ispiecewise continuous and
defined by
{ 2t 0t1
g(t) =
3 1<t2
Evaluate
∫ 1
(a) g(t)dt
0
∫ 1.5
(b) g(t)dt
0
∫ 1.7
(c) g(t)dt
0.5
∫ 2
(d) g(t)dt
1
∫ 1.5
(e) g(t)dt
1.3
11 Given
⎧
⎨1+t −1t<3
f(t)= t−1 3t4
⎩
0 otherwise
evaluate
∫ 2
(a) f(t)dt
−1
∫ 4
(b) f(t)dt
−1
∫ 5
(c) f(t)dt
0
∫ ∞
(d) f(t)δ(t −2)dt
−∞
∫ ∞
(e) f(t)u(t)dt
−∞