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[

Example16.1 Show that f (x) =xandg(x) =x −1 areorthogonal on 0, 3 ]

.

2

16.2 Orthogonal functions 481

Solution

] 3/2

∫ 3/2 ∫ 3/2

[ x

x(x−1)dx= x 2 3

−xdx=

0

0 3 − x2

2

0

[

Hence f andgare orthogonal over the interval 0, 3 ]

.

2

= 9 8 − 9 8 = 0

Clearlyfunctionsmaybeorthogonaloveroneintervalbutnotorthogonaloverothers.

For example,

∫ 1

0

x(x−1)dx≠0

and soxandx −1 arenotorthogonal over [0,1].

Example16.2 Show f (t) = 1,g(t) = sint andh(t) = cost aremutually orthogonal over [−π,π].

Solution We are required toshow thatany pairoffunctions isorthogonal over [−π,π].

∫ π

−π

1sintdt =[−cost] π −π = −cosπ +cos(−π)

∫ π

−π

= −(−1) + (−1) =0

1costdt =[sint] π −π = sinπ −sin(−π) =0

Usingthe trigonometricidentitysin2A = 2sinAcosA, wecan write

∫ π

−π

sintcostdt =

∫ π

−π

[

1 cos(2t)

2 sin(2t)dt = − 4

cos(2π) −cos(−2π)

= − = 0

4

] π

−π

Hence the functions 1,sint, cost form an orthogonal set over [−π,π].

ThesetofExample 16.2 maybeextendedto

{1,sint,cost,sin(2t),cos(2t),sin(3t),cos(3t),...,sin(nt),cos(nt)}

n ∈ N

Example16.3 Verifythat {1,sint,cost,sin(2t),cos(2t),...} formsanorthogonal setover [−π,π].

Solution Supposen,m ∈ N. We must show that all combinations of 1,sinnt, sinmt, cosnt and

cosmt are orthogonal.

∫ π

[ −cos(nt) −cos(nπ) +cos(−nπ)

1sin(nt)dt =

= = 0

n n

−π

] π

−π

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