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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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434 Chapter 13 Integration

(m)

(n)

(o)

(p)

e t +e −t dt=e t −e −t +c

3sec(4x −1)dx = 3 ln|sec(4x −1) +tan(4x −1)| +c

4

2cot9xdx= 2 9 ln|sin9x|+c

7cosec(π/3) dx = {7cosec(π/3)}x +c

as cosec(π/3) isaconstant

Engineeringapplication13.1

Distancetravelledbyaparticle

The speed, v, of a particle is the rate of change of distance,s, with respect to timet,

thatis v = ds .Thespeedattimet isgivenby3+2t.ThisisillustratedinFigure13.1.

dt

Note that the speed of the particle is increasing linearly with time. Find the distance

intermsoft.

Solution

We aregiven that

v = ds

dt =3+2t

and arerequired tofinds. Therefore,

s = 3+2tdt=3t+t 2 +c

Notethatthespeedoftheparticleismodelledbyalinearexpressionint.Thismeans

thatthespeedincreasesbythesameamountineachsubsequentsecond.Ontheother

hand,thedistance,s,ismodelledbyaquadraticint.Therefore,thedistancetravelled

ineachsubsequentsecondincreases.Figure13.1illustratesthespeed-timegraphand

Figure 13.2 illustratesthe distance-time graph.

y

s

3

c

O

Figure13.1

Graphofspeed ofthe particle, v,against

time,t.

t

O

Figure13.2

Graphofdistancetravelled by the

particle,s,against time,t.

t

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