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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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10.8 Differentiation as a linear operator 379

For a fixed temperature the only variables in this equation are I andV. We can

differentiate thisequation togive

dI

dV ≈I q

S

nkT e qV

nkT

Back substituting the approximate expressionI ≈I S

e qV

nkT into this equation yields

dI

dV ≈I q

S

nkT e qV q

nkT ≈

nkT I

Inverting this equation gives

dV

dI ≈ nkT

qI

Itisconstructiveatthisstagetocomparethisresultwiththestaticequivalent,V =IR,

from which

V

I =R

The quantity dV

dI can be thought of as a dynamic value of the diode resistance,r d ,

which varies depending on the value of the current in the diode. It is valid for a

positive voltageV that is sufficiently large to ensure the diode is in the exponential

portion of the electrical characteristic.

Engineeringapplication10.5

Operatingpointforanidealsemiconductordiode

In Engineering application 2.18 we examined the mathematical model of a semiconductordiodeandthenconsideredthespecialisedcaseofanidealdiode.Atroom

temperaturetheequationdescribingthebehaviourofitselectricalcharacteristicswas

I =I s

(e 40V −1)

where I is the diode current,V is the applied voltage and I s

is the constant reverse

saturation current. Sometimes when a diode is used in a circuit it may be biased

to operate in a certain region of its I--V characteristic. This means that its use is

restricted to a certain voltage range. The point around which it operates is known as

its operating point. This isillustratedinFigure 10.17.

Deviationsfromthisoperatingpointmaybesmallincertaincases.Ifso,theyare

known assmall-signalvariations andarecausedbysmalla.c.voltagesbeingsuperimposedonthemaind.c.biasvoltage.Incalculatinghowthediodewillreacttosuch

small-signalvoltages,theslopeofthediodecharacteristicaroundtheoperatingpoint

is more relevant than the overall ratio of current to voltage. Provided the deviations

from the operating point are not large, the tangent to theI--V curve at the operating

point provides an adequate model for how the diode will behave. The slope of the

curve can beobtained by differentiating the diodeequation.If

then

I =I s

(e 40V −1) =I s

e 40V −I s

dI

dV = 40I s e40V

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