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10.6 Existence of derivatives 371

x = a. The function shown in Figure 10.14(b) is continuous but has a cusp or corner

atx = a. In both cases it is impossible to draw a tangent atx = a, and so dy does not

dx

existatx =a.Itisimpossibletodrawatangent toacurve atapointwhere thecurve is

not smooth. Note from Figure 10.14(b) that continuity is not sufficient to guarantee the

existence of a derivative.

Example10.10 Sketch the following functions. State the values oft for which the derivative does not

exist.

(a) y=|t| (b) y=tant (c) y=1/t

Solution (a) Thegraphofy = |t|isshowninFigure10.15(a).Acornerexistsatt = 0andsothe

derivative doesnotexist here.

(b) A graph ofy = tant is shown in Figure 10.15(b). There is a discontinuity in tant

when t = ... −3π/2,−π/2,π/2,3π/2,.... No derivative exists at these

points.

(c) Figure 10.15(c) shows a graph of y = 1/t. The function has one discontinuity at

t = 0,and so the derivative doesnotexist here.

y

y = tan t

y

y

y = |t|

p

p

2

2

t

y = 1_ t

t

(a)

t

(b)

Figure10.15

(a) There is acorner att = 0; (b)tant has discontinuities; (c)y = 1/t has a discontinuity att = 0.

(c)

EXERCISES10.6

1 Sketchthe functionsanddetermineany pointswhere

aderivative does notexist.

(a) y= 1

t −1

(b) y=|sint|

(c) y=e t

(d) y = |1/t|

{ 1 t0

(e) The unitstepfunctionu(t) =

0 t<0

{ ct t0

(f) The ramp function f (t) =

0 t<0

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