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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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360 Chapter 10 Differentiation

whenxisnear,butdistinctfrom,0?’FromFigure10.6weseeyisnearto1,thatis

lim y = 1

x→0

Example10.3 The functiony(x) isdefined by

⎨0 x0

y(x) = x 0<x2

x−2 x>2

(a) Sketch the function.

(b) State the limitofyasxapproaches (i)3,(ii)2,(iii)0.

Solution (a) ThefunctionisshowninFigure10.7.Notethatthefigurehasthreeparts;eachpart

corresponds toapartinthe algebraic definition.

(b) (i) Asx → 3,the relevant partof the function isy(x) =x −2.Hence

lim y = 1

x→3

(ii) Supposex < 2 and gradually increases, approaching the value 2. Then, from

the graph, we see that y approaches 2. Now, suppose x > 2 and gradually

decreases,tendingto2.Inthiscaseyapproaches0.Hence,wecannotfindthe

limitofyasxtends to2.The lim x→2

ydoes notexist.

(iii) Asxtends to 0,ytends to 0. This is true whetherxapproaches 0 from below,

thatisfrom the left,orfrom above, thatisfrom the right.So,

lim y = 0

x→0

y

y = x

y = x – 2

y = 0

2

x

Figure10.7

Thefunctionyhas different limitsasx → 2

from the left and the right.

Itisappropriateatthisstagetointroducetheconceptofleft-handandright-handlimits.

ReferringtoExample10.3,weseethatasxapproaches2fromtheleft,thatisfrombelow,

then y approaches 2. We say that the left-hand limit of y as x tends to 2 is 2. This is

written as

lim

x→2 −y = 2

Similarly, the right-hand limit ofyis obtained by lettingxtend to 2 from above. In this

case,yapproaches0.This iswritten as

lim

x→2 +y = 0

Consider a point at which the left-hand and right-hand limits are equal. At such a point

wesay ‘thelimitexists atthatpoint’.

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