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082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

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7.3 Cartesian components 237

Engineeringapplication7.4

Robotpositions

Positionvectorsprovideausefulmeansofdeterminingthepositionofarobot.There

aremanydifferenttypesofrobotbutacommontypeusesaseriesofrigidlinksconnected

together by flexible joints. Usually the mechanism is anchored at one point.

Atypical example isillustratedinFigure 7.23.

b

c

d

Y

a

p

X

Figure7.23

Atypical robot configuration with vectors representing

the robot links.

TheanchorpointisXandthetipoftherobotissituatedatpointY.Thefinallink

is sometimes called the hand of the robot. The hand often has rotating and gripping

facilitiesanditssizerelativetotherestoftherobotisusuallyquitesmall.Eachofthe

robotlinkscanberepresentedbyavector(seeFigure7.23).Thevectordcorresponds

tothehand.Acommonrequirementinroboticsistobeabletocalculatetheposition

of the tip of the hand to ensure it does not collide with other objects. This can be

achieved by defining a set of Cartesian coordinates with origin at the anchor point

of the robot, X. Each of the link vectors can then be represented in terms of these

coordinates. For example, inthe case of the robot inFigure 7.23:

a=a 1

i+a 2

j+a 3

k

b=b 1

i+b 2

j+b 3

k

c=c 1

i+c 2

j+c 3

k

d=d 1

i+d 2

j+d 3

k

Thepositionofthetipofthehandcanbecalculatedbyaddingtogetherthesevectors.

So,

p=a+b+c+d

=(a 1

+b 1

+c 1

+d 1

)i+(a 2

+b 2

+c 2

+d 2

)j+(a 3

+b 3

+c 3

+d 3

)k

7.3.2 Linearcombinations,dependenceandindependence

Supposewehavetwovectorsaandb.Ifweformarbitraryscalarmultiplesofthese,that

isk 1

a andk 2

b, and add these together, we obtain a new vector c where c = k 1

a+k 2

b.

The vector c is said to be a linear combination of a and b. Note that scalar multiplication

and addition of vectors are the only operations allowed when forming a linear

combination. Vector c is said to depend linearly on a and b. Of course we could also

write

a = 1 k 1

c − k 2

k 1

b providedk 1 ≠ 0

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