25.08.2021 Views

082-Engineering-Mathematics-Anthony-Croft-Robert-Davison-Martin-Hargreaves-James-Flint-Edisi-5-2017

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

6.4 The binomial theorem 217

EXERCISES6.4

1 Usethe binomial theorem to expand

(a) (1 +x) 3 (b) (1 +x) 4 (c)

(d)

(

1 − x 2) 5

(e)

(

2 + x 2) 5

(f)

2 UsePascal’striangleto expand (a +b) 8 .

(

(

1 + x 3

3 − x 4

3 UsePascal’striangleto expand (2x +3y) 4 .

4 Expand (a −2b) 5 .

5 Usethe binomial theoremto findthe expansion of

(3 −2x) 6 upto andincluding the term inx 3 .

6 Obtainthe firstfour terms in the expansion of

(

1 + 1 2 x ) 10

.

7 Obtainthe firstfive termsin the expansion of

(1 +2x) 1/2 .Statethe rangeofvalues ofxforwhich

the expansion is valid.Chooseavalue ofxwithin the

rangeofvalidity andcomputevalues ofyour

expansionforcomparison with the truefunction

values. (

8 Expand 1 + 1 ) −4

2 x in ascending powersofxupto

the term inx 4 ,stating the range ofvalues ofxfor

whichthe expansion is valid.

(

9 Expand 1 + 1 −1/2

in descending powers upto the

x)

fourthterm.

) 4

) 4

10 (a) Expand (1 +x 2 ) 4 .

(b) Expand (1 +1/x 2 ) 4 .

11 A function, f (x),isgiven by

( ) 1/2

f(x)=

1 + 1 x

(a) Obtain the firstfour termsin the expansion of

f (x)in descending powersofx.State the range

ofvalues ofxforwhich the expansion is valid.

(b) By writing f (x)in the form

f(x) =x −1/2 (1 +x) 1/2

obtain the firstfourterms in the expansion of

f (x)in ascending powersofx.State the range of

values ofxforwhich the expansion is valid.

12 The function,g(x),is defined by

g(x) =

1

(1+x 2 ) 4

(a) Obtain the firstfour termsin the expansion of

g(x) in ascending powersofx. Statethe range of

values ofxforwhich the expansion is valid.

(b) By rewritingg(x) in an appropriate form,obtain

the firstfour termsin the expansion ofg(x) in

descending powers ofx.State the range ofvalues

ofxforwhich the expansion isvalid.

Solutions

1 (a) 1+3x+3x 2 +x 3

3 16x 4 +96x 3 y +216x 2 y 2 +216xy 3 +81y 4

(b) 1+4x+6x 2 +4x 3 +x 4

4 a 5 −10a 4 b +40a 3 b 2 −80a 2 b 3 +80ab 4 −32b 5

(c) 1+ 4x

3 + 2x2

3 + 4x3

27 + x4

5 729 −2916x +4860x 2 −4320x 3

81

(d) 1− 5x

2 + 5x2

2 − 5x3

4 + 5x4

16 − x5 6 1+5x+ 45x2 +15x 3

32

4

(e) 32 +40x +20x 2 +5x 3 + 5x4

8 + x5 7 1+x− x2

32

2 + x3

2 − 5x4

8 valid for −1 2 <x< 1 2

(f) 81 −27x + 27x2 − 3x3

8 16 + x4 8 1−2x+ 5x2

256

2 − 5x3

2 + 35x4 valid for −2 <x<2

16

2 a 8 +8a 7 b +28a 6 b 2 +56a 5 b 3 +70a 4 b 4 +56a 3 b 5 + 9 1 − 1

28a 2 b 6 +8ab 7 +b 8 2x + 3

8x2 − 5

16x 3

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!