Advanced Waterworks Mathematics, 2019a

More documents

Recommendations

Info

Since only half a sphere is capping the pipe, we need to divide the total surface area by two to get the actual area for this problem. Half the Surface Area = 8.757146 ft 2 2 = 4.378573 ft = 4.38 ft 2 2 The entire interior surface area is the sum of the pipe surface area and the surface area of the half sphere. 2 2 2 Total Area = 1,835.33 ft 4.38 ft 1,839.71 ft 36 | A dvanced Waterworks Mathematics
Practice Problems 2.1 1. What is the area of the opening of a 21” diameter pipe? 2. What is the cross-sectional area of a rectangular channel that has a width of 5 feet 8 inches and a height of 8 feet 5 inches? 3. A trapezoidal channel is 12 feet wide at the bottom and 22 feet wide at the water line when the water is 7 feet deep. What is the cross-sectional area of the channel? 4. A 35-foot diameter spherical tank needs to be painted. If one gallon of paint will cover 400 sf, how many gallons of paint will be required to put two coats of paint on the exterior of the tank? 5. What is the surface area of a 45-foot tall standpipe with a diameter of 20 feet? 37 | A dvanced Waterworks Mathematics
Page 1 and 2: 1 | A dvanced Waterworks Mathematic
Page 3 and 4: Acknowledgements College of the Can
Page 5 and 6: Unit 10 201 10.1 Horsepower and Eff
Page 7 and 8: Multiple units may need to be conve
Page 9 and 10: Practice Problems 1.1a Show how eac
Page 11 and 12: Word problems may involve unit conv
Page 13 and 14: 6. A pipe flows at a rate of 6.3 cf
Page 15 and 16: 6. A well flows at a rate of 1,250
Page 17 and 18: Well 2: Total Flow in MGD 1,000 gal
Page 19 and 20: Practice Problems 1.2 1. A water ut
Page 21 and 22: 3. A water utility has 12,300 servi
Page 23 and 24: The shape of a tank is often a cyli
Page 25 and 26: Circles A circle is a round figure
Page 27 and 28: Example: What is the area of an 813
Page 29 and 30: Trapezoids Trapezoids are four-side
Page 31 and 32: Figure 2.9 9 Circumference of a Cir
Page 33 and 34: The formula for the area of a spher
Page 35: Example: What is the entire interio
Page 39 and 40: 8. What is the entire interior surf
Page 41 and 42: 5. A standpipe needs to be painted.
Page 43 and 44: Then, calculate the volume of the t
Page 45 and 46: 2 1 2 Trapezoidal Prism = H L 8.5
Page 47 and 48: Practice Problems 2.2 1. What is th
Page 49 and 50: Exercise 2.2 1. What is the volume
Page 51 and 52: 2.3 AREA AND VOLUME WORD PROBLEMS W
Page 53 and 54: Figure 2.20 19 Step 4: Put the info
Page 55 and 56: Step 3: Make a sketch to clarify th
Page 57 and 58: Figure 2.22 21 When looking at a pr
Page 59 and 60: Calculate the volume of the cylinde
Page 61 and 62: 4. A water tank truck delivered 30
Page 63 and 64: Exercise 2.3 1. A water utility ope
Page 65 and 66: 6. A private contractor needs water
Page 67 and 68: 2.4 FLOW RATE Flow rate is the meas
Page 69 and 70: Key Terms circumference - the dist
Page 71 and 72: 4. What is the diameter of a pipe t
Page 73 and 74: 4. What is the diameter of a pipe t
Page 75 and 76: Substance Specific Gravity Weight C
Page 77 and 78: 5. The specific gravity of 25% Alum
Page 79 and 80: 5. The specific gravity of 25% Alum
Page 81 and 82: To convert between a percentage and
Page 83 and 84: And now we are moving to the row fo
Page 85 and 86: Practice Problems 3.2 1. An 87.5% c
Page 87 and 88:
Exercise 3.2 Solve the following pr
Page 89 and 90:
3.3 MIXING AND DILUTING SOLUTIONS T
Page 91 and 92:
Total Volume of the new solution is
Page 93 and 94:
3. A chlorine storage tank that is
Page 95 and 96:
3. A chlorine storage tank that is
Page 97 and 98:
The following charts or Pie Wheels
Page 99 and 100:
At only a 10% concentration, you wi
Page 101 and 102:
Now the question is asking how many
Page 103 and 104:
Key Terms chlorine demand - the
Page 105 and 106:
3. How many pounds of 24.5% sodium
Page 107 and 108:
7. A water treatment operator adjus
Page 109 and 110:
11. An operator added 422 gallons o
Page 111 and 112:
3. How many pounds of 12.5% sodium
Page 113 and 114:
7. A water treatment operator adjus
Page 115 and 116:
11. An operator added 275 gallons o
Page 117 and 118:
Weirs can either be sharp-crested o
Page 119 and 120:
Weir Overflow Rate (gpm/ft) = ? gpm
Page 121 and 122:
Key Terms weir - an overflow stru
Page 123 and 124:
5. A treatment plant processes 8.4
Page 125 and 126:
5. A treatment plant processes 15 M
Page 127 and 128:
UNIT 6 6.1 DETENTION TIME Detention
Page 129 and 130:
D = t Volume Flow gallons million
Page 131 and 132:
Rearranging the terms in the detent
Page 133 and 134:
3. A water utility engineer is desi
Page 135 and 136:
7. A 70-foot diameter, 35-foot-deep
Page 137 and 138:
3. A water utility engineer is desi
Page 139 and 140:
7. The chlorine residual decay rate
Page 141 and 142:
11. A circular clarifier processes
Page 143 and 144:
Although filtration rates are commo
Page 145 and 146:
Key Terms contact time - detenti
Page 147 and 148:
4. A water treatment plant processe
Page 149 and 150:
Exercise 6.2 1. A water treatment p
Page 151 and 152:
7. An Engineer is designing a circu
Page 153 and 154:
Pin It! Misconception Alert Sometim
Page 155 and 156:
Next, there are two crucial terms t
Page 157 and 158:
Finding the Correct CT Table Typica
Page 159 and 160:
and resulting disinfection inactiva
Page 161 and 162:
plant maintains a chloraminated res
Page 163 and 164:
Practice Problems 7.1 1. What is th
Page 165 and 166:
5. A conventional water treatment p
Page 167 and 168:
7. A direct filtration plant is ope
Page 169 and 170:
Page 171 and 172:
6. A direct filtration water treatm
Page 173 and 174:
UNIT 8 8.1 PRESSURE Pressure is the
Page 175 and 176:
From this example, it is clear that
Page 177 and 178:
Page 179 and 180:
5. Two houses are served by a nearb
Page 181 and 182:
Page 183 and 184:
8.2 HEAD LOSS As water travels thro
Page 185 and 186:
Friction will need to be added at t
Page 187 and 188:
3. A well located at 200 feet above
Page 189 and 190:
Page 191 and 192:
UNIT 9 9.1 WELL YIELD, SPECIFIC CAP
Page 193 and 194:
Cone of Depression The triangular s
Page 195 and 196:
Practice Problems 9.1 1. A well has
Page 197 and 198:
7. A well has a specific capacity o
Page 199 and 200:
4. A well has an hour meter attache
Page 201 and 202:
UNIT 10 10.1 HORSEPOWER AND EFFICIE
Page 203 and 204:
The above equation is used to calcu
Page 205 and 206:
Practice Problems 10.1 1. What is t
Page 207 and 208:
Exercise 10.1 Calculate the require
Page 209 and 210:
10.2 HEAD LOSS AND HORSEPOWER As di
Page 211 and 212:
Practice Problems 10.2 1. A well is
Page 213 and 214:
Exercise 10.2 Calculate the followi
Page 215 and 216:
10.3 CALCULATING POWER COSTS It is
Page 217 and 218:
93.25 kW $ 0.088 8.33 hr $ 68.35
Page 219 and 220:
Practice Problems 10.3 1. A well fl
Page 221 and 222:
4. A well draws water from an aquif
Page 223 and 224:
7. Complete the table below based o
Page 225 and 226:
Exercise 10.3 Solve the following p
Page 227 and 228:
4. A well draws water from an aquif
Page 229 and 230:
7. Complete the table below based o
Page 231 and 232:
UNIT 11 11.1 PER CAPITA WATER USE A
Page 233 and 234:
That’s a lot of gallons. This is
Page 235 and 236:
Green Building Code) has resulted i
Page 237 and 238:
Page 239 and 240:
7. A water district has a goal of 1
Page 241 and 242:
4. How much water would a family of
Page 243 and 244:
UNIT 12 12.1 BLENDING AND DILUTING
Page 245 and 246:
To determine the percentage of Sour
Page 247 and 248:
Practice Problems 12.1 1. A well ha
Page 249 and 250:
5. Two wells need to achieve a dail
Page 251 and 252:
3. A well with a PCE level of 7.5 u
Page 253 and 254:
UNIT 13 13.1 SCADA AND THE USE OF M
Page 255 and 256:
ottom to what is referred to as the
Page 257 and 258:
mA (reading) - mA (offset) = percen
Page 259 and 260:
4. A water tank is 52 ft tall and h
Page 261 and 262:
8. A chemical injection system is m
Page 263 and 264:
4. A water tank is 45 ft tall and h
Page 265 and 266:
8. A chemical injection system is m
Page 267 and 268:
mean extra funds to pay for securit
Page 269 and 270:
Per the table, the total annual bud
Page 271 and 272:
Pumps and Motors: $72,000 x% $6,2
Page 273 and 274:
Variable Costs Reason 273 | A dvanc
Page 275 and 276:
Practice Problems 14.1 1. A utility
Page 277 and 278:
3. A utility has annual operating e
Page 279 and 280:
7. A small water company has a tota
Page 281 and 282:
2. A pump that has been in operatio
Page 283 and 284:
5. A 250 hp well operates 9 hours a
Page 285 and 286:
PRACTICE PROBLEM SOLUTIONS Practice
Page 287 and 288:
3.1 cf 3,600 sec 10 hr 7.48 gal 30
Page 289 and 290:
1,346,400 gal 1 AF 365 day day 3
Page 291 and 292:
Page 293 and 294:
Page 295 and 296:
Practice Problems 2.3 1. A water ut
Page 297 and 298:
3 22 ft 217,800.13 ft = depth ft
Page 299 and 300:
Q (cfs) 3.18 cfs A (ft ) = = = 1.17
Page 301 and 302:
5. The specific gravity of 25% Alum
Page 303 and 304:
To convert ppb to ppm, you divide p
Page 305 and 306:
Practice Problems 3.3 1. How many g
Page 307 and 308:
Practice Problems 4.1 1. How many g
Page 309 and 310:
6.35 MG 8.34 lbs 2,914.5 lbs ppm
Page 311 and 312:
8. A water utility produced 6,000 A
Page 313 and 314:
72,327.816 lbs 72,327.816 lbs 72,32
Page 315 and 316:
Weir Length (ft) = 4,791.67 gpm 41
Page 317 and 318:
quality objectives of a certain tre
Page 319 and 320:
12 MG 1,000,000 gal 1 day 1 hour
Page 321 and 322:
8. A circular clarifier processes 9
Page 323 and 324:
4. A water treatment plant processe
Page 325 and 326:
4,700,000 gal 1 day ? min = 1,554.
Page 327 and 328:
Page 329 and 330:
Now look at Table C-7 Inactivation
Page 331 and 332:
500 mg/L min CT is required. Locati
Page 333 and 334:
Location and Type of Disinfection T
Page 335 and 336:
Page 337 and 338:
2 2 D = 0.33121019 ft 12 in D = 0.5
Page 339 and 340:
5. A water utility has two differen
Page 341 and 342:
gpm Specific Capacity = ft 717.5 gp
Page 343 and 344:
Page 345 and 346:
3. A well with pumps located 46 ft
Page 347 and 348:
(630 gpm)(130 ft) 65 hp = (3,960)(?
Page 349 and 350:
electrical rate of $0.111 per kW-Hr
Page 351 and 352:
(flow rate in gallons per minute)(t
Page 353 and 354:
2 flushes per family member 6 famil
Page 355 and 356:
Practice Problems 12.1 1. A well ha
Page 357 and 358:
-137.5 mg/L ? mg/L = = 275 mg/L - (
Page 359 and 360:
Practice Problems 13.1 1. A 4-20 mA
Page 361 and 362:
7. A water utility uses a 4-20 mA s
Page 363 and 364:
NEW PUMP: (450 gpm)(65 ft) Motor hp
Page 365 and 366:
Total operational cost per year. $2
Page 367 and 368:
CT TABLES APPENDIX 367 | A dvanced
Page 369 and 370:
69 | A dvanced Waterworks Mathemati
Page 371 and 372:
Page 373 and 374:
Page 375 and 376:
Page 377 and 378:
Page 379 and 380:
Page 381 and 382:
381 | A dvanced Waterworks Mathemat
Page 383 and 384:
383 | A dvanced Waterworks Mathemat
show all

Advanced Waterworks Mathematics, 2019a

Create successful ePaper yourself

Delete template?

Save as template?