Advanced Waterworks Mathematics, 2019a

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Practice Problems 3.1 1. Liquid sodium hypochlorite has a specific gravity of 1.69. What is the corresponding weight in pounds per gallon? 8.34 lbs/gal lbs lbs 1.69 SG = 14.0946 = 14.1 1 SG gal gal 2. Chlorine gas is cooled and pressurized into a liquid state. It weighs 17.31 lbs/gal. What is the specific gravity? 1 SG 8.34 lbs/gal 17.31 lbs/gal = 2.07553 SG = 2.08 SG 3. What is the weight difference between 111 gallons of water and 61 gallons of sodium hypochlorite with a specific gravity of 1.37? Water: 111 gal 8.34 lbs gal = 925.74 lbs 8.34 lbs/gal 11.43 lbs Sod. Hypo.: 61 gal 1.37 SG = 61 gal = 697.23 lbs 1 SG gal Weight Difference = 925.74 lbs - 697.23 lbs = 228.51 lbs 4. A treatment operator has 75 gallons of 14.5% sodium hypochlorite. How many pounds of the 75 gallons are available chlorine? 75 gal 0.145 = 10.875 gal of sodium hypochlorite 8.34 lbs 10.875 gal = 90.6975 lbs = 90.7 lbs of sodium hypochlorite gal Total Pounds: 75 gal 8.34 lbs gal = 625.5 lbs 300 | A dvanced Waterworks Mathematics
5. The specific gravity of 25% Alum is 1.24. How much does 83 gallons of 25% Alum weigh? 8.34 lbs/gal 10.3416 lbs 1.24 SG 83 gal = 83 gal = 858.3528 lbs = 858.4 lbs 1 SG gal 6. Ferric chloride weighs 19.44 lbs/gal. What is the specific gravity? 19.44 lbs gal gal 8.34 lbs = 2.33 SG 7. How many pounds of ferric chloride are in 92 gallons of 33% strength? (Assume the specific gravity is 1.52.) 8.34 lbs/gal 4.18 lbs 0.33 1.52 SG 92 gal = 92 gal = 384.56 lbs 1 SG gal 8. What is the weight in lbs/cf of a substance that has a specific gravity of 1.47? weight in lbs/gal = 8.34 lbs/gal 1 SG 1.47 SG = 12.2598 lbs/gal = 12.26 lbs/gal 12.26 lbs 7.48 gal = 91.7048 lbs/cf = 91.7 lbs/cf gal 1 cf 9. A shipment of crude oil has a specific gravity of 0.674. What is the weight in lbs/cf? weight in lbs/gal = 8.34 lbs/gal 1 SG 0.674 SG = 5.62116 lbs/gal = 5.6 lbs/gal 5.6 lbs 7.48 gal = 41.888 lbs/cf = 41.9 lbs/cf gal 1 cf 301 | A dvanced Waterworks Mathematics
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1 | A dvanced Waterworks Mathematic
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Acknowledgements College of the Can
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Unit 10 201 10.1 Horsepower and Eff
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Multiple units may need to be conve
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Practice Problems 1.1a Show how eac
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Word problems may involve unit conv
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6. A pipe flows at a rate of 6.3 cf
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6. A well flows at a rate of 1,250
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Well 2: Total Flow in MGD 1,000 gal
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Practice Problems 1.2 1. A water ut
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3. A water utility has 12,300 servi
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The shape of a tank is often a cyli
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Circles A circle is a round figure
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Example: What is the area of an 813
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Trapezoids Trapezoids are four-side
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Figure 2.9 9 Circumference of a Cir
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The formula for the area of a spher
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Example: What is the entire interio
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Practice Problems 2.1 1. What is th
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8. What is the entire interior surf
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5. A standpipe needs to be painted.
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Then, calculate the volume of the t
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2 1 2 Trapezoidal Prism = H L 8.5
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Exercise 2.2 1. What is the volume
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2.3 AREA AND VOLUME WORD PROBLEMS W
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Figure 2.20 19 Step 4: Put the info
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Step 3: Make a sketch to clarify th
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Figure 2.22 21 When looking at a pr
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Calculate the volume of the cylinde
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4. A water tank truck delivered 30
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Exercise 2.3 1. A water utility ope
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6. A private contractor needs water
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2.4 FLOW RATE Flow rate is the meas
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Key Terms circumference - the dist
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4. What is the diameter of a pipe t
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4. What is the diameter of a pipe t
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Substance Specific Gravity Weight C
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5. The specific gravity of 25% Alum
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5. The specific gravity of 25% Alum
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To convert between a percentage and
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And now we are moving to the row fo
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Practice Problems 3.2 1. An 87.5% c
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Exercise 3.2 Solve the following pr
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3.3 MIXING AND DILUTING SOLUTIONS T
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Total Volume of the new solution is
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3. A chlorine storage tank that is
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3. A chlorine storage tank that is
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The following charts or Pie Wheels
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At only a 10% concentration, you wi
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Now the question is asking how many
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Key Terms chlorine demand - the
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3. How many pounds of 24.5% sodium
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7. A water treatment operator adjus
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11. An operator added 422 gallons o
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3. How many pounds of 12.5% sodium
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7. A water treatment operator adjus
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11. An operator added 275 gallons o
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Weirs can either be sharp-crested o
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Weir Overflow Rate (gpm/ft) = ? gpm
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Key Terms weir - an overflow stru
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5. A treatment plant processes 8.4
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5. A treatment plant processes 15 M
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UNIT 6 6.1 DETENTION TIME Detention
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D = t Volume Flow gallons million
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Rearranging the terms in the detent
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3. A water utility engineer is desi
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7. A 70-foot diameter, 35-foot-deep
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3. A water utility engineer is desi
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7. The chlorine residual decay rate
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11. A circular clarifier processes
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Although filtration rates are commo
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Key Terms contact time - detenti
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4. A water treatment plant processe
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Exercise 6.2 1. A water treatment p
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7. An Engineer is designing a circu
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Pin It! Misconception Alert Sometim
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Next, there are two crucial terms t
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Finding the Correct CT Table Typica
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and resulting disinfection inactiva
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plant maintains a chloraminated res
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5. A conventional water treatment p
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7. A direct filtration plant is ope
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4. A conventional water treatment p
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6. A direct filtration water treatm
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UNIT 8 8.1 PRESSURE Pressure is the
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From this example, it is clear that
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5. Two houses are served by a nearb
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8.2 HEAD LOSS As water travels thro
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Friction will need to be added at t
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3. A well located at 200 feet above
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UNIT 9 9.1 WELL YIELD, SPECIFIC CAP
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Cone of Depression The triangular s
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Practice Problems 9.1 1. A well has
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7. A well has a specific capacity o
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4. A well has an hour meter attache
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UNIT 10 10.1 HORSEPOWER AND EFFICIE
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The above equation is used to calcu
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Practice Problems 10.1 1. What is t
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Exercise 10.1 Calculate the require
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10.2 HEAD LOSS AND HORSEPOWER As di
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Practice Problems 10.2 1. A well is
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Exercise 10.2 Calculate the followi
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10.3 CALCULATING POWER COSTS It is
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93.25 kW $ 0.088 8.33 hr $ 68.35
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Practice Problems 10.3 1. A well fl
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4. A well draws water from an aquif
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7. Complete the table below based o
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Exercise 10.3 Solve the following p
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4. A well draws water from an aquif
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7. Complete the table below based o
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UNIT 11 11.1 PER CAPITA WATER USE A
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That’s a lot of gallons. This is
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Green Building Code) has resulted i
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Practice Problems 11.1 1. What is t
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7. A water district has a goal of 1
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4. How much water would a family of
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UNIT 12 12.1 BLENDING AND DILUTING
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To determine the percentage of Sour
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Practice Problems 12.1 1. A well ha
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Page 253 and 254: UNIT 13 13.1 SCADA AND THE USE OF M
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Page 261 and 262: 8. A chemical injection system is m
Page 263 and 264: 4. A water tank is 45 ft tall and h
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Page 267 and 268: mean extra funds to pay for securit
Page 269 and 270: Per the table, the total annual bud
Page 271 and 272: Pumps and Motors: $72,000 x% $6,2
Page 273 and 274: Variable Costs Reason 273 | A dvanc
Page 275 and 276: Practice Problems 14.1 1. A utility
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Page 279 and 280: 7. A small water company has a tota
Page 281 and 282: 2. A pump that has been in operatio
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Page 285 and 286: PRACTICE PROBLEM SOLUTIONS Practice
Page 287 and 288: 3.1 cf 3,600 sec 10 hr 7.48 gal 30
Page 289 and 290: 1,346,400 gal 1 AF 365 day day 3
Page 291 and 292: Practice Problems 2.1 1. What is th
Page 295 and 296: Practice Problems 2.3 1. A water ut
Page 297 and 298: 3 22 ft 217,800.13 ft = depth ft
Page 299: Q (cfs) 3.18 cfs A (ft ) = = = 1.17
Page 303 and 304: To convert ppb to ppm, you divide p
Page 305 and 306: Practice Problems 3.3 1. How many g
Page 307 and 308: Practice Problems 4.1 1. How many g
Page 309 and 310: 6.35 MG 8.34 lbs 2,914.5 lbs ppm
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Page 313 and 314: 72,327.816 lbs 72,327.816 lbs 72,32
Page 315 and 316: Weir Length (ft) = 4,791.67 gpm 41
Page 317 and 318: quality objectives of a certain tre
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Page 321 and 322: 8. A circular clarifier processes 9
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Page 325 and 326: 4,700,000 gal 1 day ? min = 1,554.
Page 327 and 328: 4. A conventional water treatment p
Page 329 and 330: Now look at Table C-7 Inactivation
Page 331 and 332: 500 mg/L min CT is required. Locati
Page 333 and 334: Location and Type of Disinfection T
Page 337 and 338: 2 2 D = 0.33121019 ft 12 in D = 0.5
Page 339 and 340: 5. A water utility has two differen
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Page 343 and 344: Practice Problems 10.1 1. What is t
Page 345 and 346: 3. A well with pumps located 46 ft
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(flow rate in gallons per minute)(t
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2 flushes per family member 6 famil
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Practice Problems 12.1 1. A well ha
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-137.5 mg/L ? mg/L = = 275 mg/L - (
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Practice Problems 13.1 1. A 4-20 mA
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7. A water utility uses a 4-20 mA s
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NEW PUMP: (450 gpm)(65 ft) Motor hp
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Total operational cost per year. $2
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CT TABLES APPENDIX 367 | A dvanced
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Advanced Waterworks Mathematics, 2019a

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