Advanced Waterworks Mathematics, 2019a

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5. Two wells need to achieve a daily flow of 3.24 MG and a total hardness level of 90 mg/L as calcium carbonate (CaCO3.) Well #1 has a total hardness level of 315 mg/L as CaCO3 and Well #2 has a level of 58 mg/L as CaCO3. What is the gpm that each well must pump? 6. The State Health Department has requested a blending plan to lower levels of sulfate from a small water utility well. The well has a constant sulfate level of 525 mg/L. The utility needs to purchase the water to blend with the well. The purchased water has a sulfate level of 135 mg/L. They need to bring the sulfate levels down to 265 mg/L and supply a demand of 1.15 MGD. The purchased water costs $550/AF. How much will the purchased water cost for the entire year? 252 | A dvanced Waterworks Mathematics
UNIT 13 13.1 SCADA AND THE USE OF MA SCADA SCADA is the acronym for Supervisory Control and Data Acquisition. It is a computerized system allowing a water system to operate automatically. This does not mean that human beings are not involved. Distribution and treatment operators learn to use SCADA to help them in their work. Figure 13.1 49 A SCADA system usually consists of three (3) basic components: field instrumentation, communications (telemetry), and some type of central control equipment. The field instrumentation will measure various parameters such as flow, chemical feed rates, chemical dosage levels, and tank levels. These instruments will then gather a series of signals and transmit them through some type of communication device(s) known as telemetry. The telemetry communication can be radio signals, telephone lines, or fiber optics. This information is sent to a central control computer typically located at an office or operations control center. 49 Photo used with permission of SCV Water 253 | A dvanced Waterworks Mathematics
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1 | A dvanced Waterworks Mathematic
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Acknowledgements College of the Can
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Unit 10 201 10.1 Horsepower and Eff
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Multiple units may need to be conve
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Practice Problems 1.1a Show how eac
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Word problems may involve unit conv
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6. A pipe flows at a rate of 6.3 cf
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6. A well flows at a rate of 1,250
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Well 2: Total Flow in MGD 1,000 gal
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Practice Problems 1.2 1. A water ut
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3. A water utility has 12,300 servi
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The shape of a tank is often a cyli
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Circles A circle is a round figure
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Example: What is the area of an 813
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Trapezoids Trapezoids are four-side
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Figure 2.9 9 Circumference of a Cir
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The formula for the area of a spher
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Example: What is the entire interio
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Practice Problems 2.1 1. What is th
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8. What is the entire interior surf
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5. A standpipe needs to be painted.
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Then, calculate the volume of the t
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2 1 2 Trapezoidal Prism = H L 8.5
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Exercise 2.2 1. What is the volume
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2.3 AREA AND VOLUME WORD PROBLEMS W
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Figure 2.20 19 Step 4: Put the info
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Step 3: Make a sketch to clarify th
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Figure 2.22 21 When looking at a pr
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Calculate the volume of the cylinde
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4. A water tank truck delivered 30
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Exercise 2.3 1. A water utility ope
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6. A private contractor needs water
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2.4 FLOW RATE Flow rate is the meas
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Key Terms circumference - the dist
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4. What is the diameter of a pipe t
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4. What is the diameter of a pipe t
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Substance Specific Gravity Weight C
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5. The specific gravity of 25% Alum
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5. The specific gravity of 25% Alum
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To convert between a percentage and
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And now we are moving to the row fo
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Practice Problems 3.2 1. An 87.5% c
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Exercise 3.2 Solve the following pr
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3.3 MIXING AND DILUTING SOLUTIONS T
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Total Volume of the new solution is
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3. A chlorine storage tank that is
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3. A chlorine storage tank that is
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The following charts or Pie Wheels
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At only a 10% concentration, you wi
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Now the question is asking how many
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Key Terms chlorine demand - the
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3. How many pounds of 24.5% sodium
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7. A water treatment operator adjus
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11. An operator added 422 gallons o
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3. How many pounds of 12.5% sodium
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7. A water treatment operator adjus
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11. An operator added 275 gallons o
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Weirs can either be sharp-crested o
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Weir Overflow Rate (gpm/ft) = ? gpm
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Key Terms weir - an overflow stru
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5. A treatment plant processes 8.4
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5. A treatment plant processes 15 M
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UNIT 6 6.1 DETENTION TIME Detention
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D = t Volume Flow gallons million
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Rearranging the terms in the detent
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3. A water utility engineer is desi
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7. A 70-foot diameter, 35-foot-deep
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3. A water utility engineer is desi
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7. The chlorine residual decay rate
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11. A circular clarifier processes
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Although filtration rates are commo
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Key Terms contact time - detenti
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4. A water treatment plant processe
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Exercise 6.2 1. A water treatment p
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7. An Engineer is designing a circu
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Pin It! Misconception Alert Sometim
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Next, there are two crucial terms t
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Finding the Correct CT Table Typica
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and resulting disinfection inactiva
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plant maintains a chloraminated res
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5. A conventional water treatment p
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7. A direct filtration plant is ope
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6. A direct filtration water treatm
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UNIT 8 8.1 PRESSURE Pressure is the
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From this example, it is clear that
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5. Two houses are served by a nearb
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8.2 HEAD LOSS As water travels thro
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Friction will need to be added at t
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3. A well located at 200 feet above
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UNIT 9 9.1 WELL YIELD, SPECIFIC CAP
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Cone of Depression The triangular s
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Practice Problems 9.1 1. A well has
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7. A well has a specific capacity o
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4. A well has an hour meter attache
Page 201 and 202: UNIT 10 10.1 HORSEPOWER AND EFFICIE
Page 203 and 204: The above equation is used to calcu
Page 205 and 206: Practice Problems 10.1 1. What is t
Page 207 and 208: Exercise 10.1 Calculate the require
Page 209 and 210: 10.2 HEAD LOSS AND HORSEPOWER As di
Page 211 and 212: Practice Problems 10.2 1. A well is
Page 213 and 214: Exercise 10.2 Calculate the followi
Page 215 and 216: 10.3 CALCULATING POWER COSTS It is
Page 217 and 218: 93.25 kW $ 0.088 8.33 hr $ 68.35
Page 219 and 220: Practice Problems 10.3 1. A well fl
Page 221 and 222: 4. A well draws water from an aquif
Page 223 and 224: 7. Complete the table below based o
Page 225 and 226: Exercise 10.3 Solve the following p
Page 227 and 228: 4. A well draws water from an aquif
Page 229 and 230: 7. Complete the table below based o
Page 231 and 232: UNIT 11 11.1 PER CAPITA WATER USE A
Page 233 and 234: That’s a lot of gallons. This is
Page 235 and 236: Green Building Code) has resulted i
Page 237 and 238: Practice Problems 11.1 1. What is t
Page 239 and 240: 7. A water district has a goal of 1
Page 241 and 242: 4. How much water would a family of
Page 243 and 244: UNIT 12 12.1 BLENDING AND DILUTING
Page 245 and 246: To determine the percentage of Sour
Page 247 and 248: Practice Problems 12.1 1. A well ha
Page 249 and 250: 5. Two wells need to achieve a dail
Page 251: 3. A well with a PCE level of 7.5 u
Page 255 and 256: ottom to what is referred to as the
Page 257 and 258: mA (reading) - mA (offset) = percen
Page 259 and 260: 4. A water tank is 52 ft tall and h
Page 261 and 262: 8. A chemical injection system is m
Page 263 and 264: 4. A water tank is 45 ft tall and h
Page 265 and 266: 8. A chemical injection system is m
Page 267 and 268: mean extra funds to pay for securit
Page 269 and 270: Per the table, the total annual bud
Page 271 and 272: Pumps and Motors: $72,000 x% $6,2
Page 273 and 274: Variable Costs Reason 273 | A dvanc
Page 275 and 276: Practice Problems 14.1 1. A utility
Page 277 and 278: 3. A utility has annual operating e
Page 279 and 280: 7. A small water company has a tota
Page 281 and 282: 2. A pump that has been in operatio
Page 283 and 284: 5. A 250 hp well operates 9 hours a
Page 285 and 286: PRACTICE PROBLEM SOLUTIONS Practice
Page 287 and 288: 3.1 cf 3,600 sec 10 hr 7.48 gal 30
Page 289 and 290: 1,346,400 gal 1 AF 365 day day 3
Page 291 and 292: Practice Problems 2.1 1. What is th
Page 293 and 294: Practice Problems 2.2 1. What is th
Page 295 and 296: Practice Problems 2.3 1. A water ut
Page 297 and 298: 3 22 ft 217,800.13 ft = depth ft
Page 299 and 300: Q (cfs) 3.18 cfs A (ft ) = = = 1.17
Page 301 and 302: 5. The specific gravity of 25% Alum
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To convert ppb to ppm, you divide p
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Practice Problems 3.3 1. How many g
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Practice Problems 4.1 1. How many g
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6.35 MG 8.34 lbs 2,914.5 lbs ppm
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8. A water utility produced 6,000 A
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72,327.816 lbs 72,327.816 lbs 72,32
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Weir Length (ft) = 4,791.67 gpm 41
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quality objectives of a certain tre
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12 MG 1,000,000 gal 1 day 1 hour
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8. A circular clarifier processes 9
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4. A water treatment plant processe
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4,700,000 gal 1 day ? min = 1,554.
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Now look at Table C-7 Inactivation
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500 mg/L min CT is required. Locati
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Location and Type of Disinfection T
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2 2 D = 0.33121019 ft 12 in D = 0.5
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5. A water utility has two differen
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gpm Specific Capacity = ft 717.5 gp
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Practice Problems 10.1 1. What is t
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3. A well with pumps located 46 ft
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(630 gpm)(130 ft) 65 hp = (3,960)(?
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electrical rate of $0.111 per kW-Hr
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(flow rate in gallons per minute)(t
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2 flushes per family member 6 famil
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Practice Problems 12.1 1. A well ha
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-137.5 mg/L ? mg/L = = 275 mg/L - (
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Practice Problems 13.1 1. A 4-20 mA
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7. A water utility uses a 4-20 mA s
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NEW PUMP: (450 gpm)(65 ft) Motor hp
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Total operational cost per year. $2
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CT TABLES APPENDIX 367 | A dvanced
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Advanced Waterworks Mathematics, 2019a

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