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API RP 581 - 3rd Ed.2016 - Add.2-2020 - Risk-Based Inspection Methodology

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RISK-BASED INSPECTION METHODOLOGY, PART 2—PROBABILITY OF FAILURE METHODOLOGY 2-99

NOTE

The t min is based on a design calculation that includes evaluation for internal pressure hoop stress,

external pressure and/or structural considerations, as appropriate. The minimum required thickness calculation

is the design code t min . Consideration for internal pressure hoop stress alone may not be sufficient. t c as

defined in STEP 5 may be used when appropriate.

2) Using Equation (2.41) with t rde from STEP 5 and FS extcorr from STEP 12.

extcorr

SRP

=

α

P⋅

D

extcorr

⋅FS

⋅trde

(2.41)

where α is the shape factor for the component type. α = 2 for a cylinder, 4 for a sphere, 1.13 for a

head.

NOTE This strength ratio parameter is based on internal pressure hoop stress only. It is not appropriate

where external pressure and/or structural considerations dominate. When t c dominates or if the t min is

calculated using another method, Equation (2.40) should be used.

n) STEP 14—Determine the number of inspections,

extcorr

N A ,

extcorr

N B ,

extcorr

N C

, and

extcorr

N D

, and the

corresponding inspection effectiveness category using Section 15.6.2 for past inspections performed

during the in-service time (see Section 4.5.5).

o) STEP 15—Determine the inspection effectiveness factors, 1 extcorr I

, I 2 extcorr

, and I 3 extcorr , using Equation

Pr extcorr

1

(2.46), prior probabilities, p Pr extcorr

2

, p

Pr extcorr

3

, and p

, from Table 4.5, conditional probabilities

(for each inspection effectiveness level), Co extcorr

p1

,

extcorr

Co p2

, and

extcorr

Co p3

, from Table 4.6, and the

extcorr

number of inspections, N A ,

from STEP 12.

extcorr

N B ,

extcorr

N C

, and

extcorr

N D

, in each effectiveness level obtained

= p ( p ) ( p ) ( p ) ( p )

=

extcorr extcorr extcorr

NA NB NC

p ( p ) ( p ) ( p ) ( p

D

)

= p ( p ) ( p ) ( p ) ( p )

extcorr extcorr extcorr extcorr

NA NB NC N

extcorr extcorr extcorrA extcorrB extcorrC extcorrD D

I1 Pr 1 Co 1 Co 1 Co 1 Co 1

extcorr extcorr extcorrA extcorrB extcorrC extcorr

I 2 Pr 2 Co 2 Co 2 Co 2 Co 2

extcorr

N D

extcorr extcorr extcorr extcorr

NA NB NC N

extcorr extcorr extcorrA extcorrB extcorrC extcorrD D

I3 Pr 3 Co 3 Co 3 Co 3 Co 3

(2.42)

Po extcorr

1

p) STEP 16—Calculate the posterior probabilities, p

(2.43) with 1 extcorr I

, I 2 extcorr , and I 3 extcorr in STEP 14.

extcorr

Po 2

, p

extcorr

Po 3

, and p

, using Equation

extcorr

extcorr

I1

Po p1

=

extcorr extcorr extcorr

I1 + I2 + I3

extcorr

extcorr

I 2

Po p2

=

extcorr extcorr extcorr

I1 + I2 + I3

extcorr

extcorr

I 3

Po p3

=

extcorr extcorr extcorr

I1 + I2 + I3

(2.43)

extcorr

q) STEP 17—Calculate the parameters, β 1 , β 2 extcorr

extcorr

, and β 3

assigning COV ∆t = 0.20, COV S f = 0.20, and COV P = 0.05.

, using Equation (2.48) and

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