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Fronts Propagating with Curvature- Dependent Speed: Algorithms ...

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ALGORITHMS FOR SURFACE MOTION PROBLEMS 17<br />

mimic Oleinik’s proof only-the more general BV case follows as in [17]. Let<br />

U(s, t) = 1 if O,(S, t) > 0, - 1 if 6Js, t) < 0, and 0 if 6,(s, t) = 0. Then,<br />

Let [si, si+,] be an interval on which 8,>0 <strong>with</strong> 8, vanishing at the end<br />

Then<br />

---- Hds<br />

=F, g 0s e/, gs si+i 1 SF’ !% !$“(‘.<br />

0<br />

4 0 g g s,<br />

The first term on the right vanishes because 6, = 0 at each end point; the second<br />

term is non-positive because -F’(O) z 0 and QSs(s,+ I) d 0 < B,,(s~). A similar<br />

argument works on intervals for which 8, < 0 in the interior and 8, vanishes at the<br />

end points. This completes the proof.<br />

Using Eqs. (2.3) and (2.4), we have<br />

K,= -[;F(K)/g]s;-K’F(K).<br />

Letting P= 1 - EK, we obtain, as in [32],<br />

and, for e = 0,<br />

K, = &Kss + EK’ - K2, (2.5)<br />

W 0)<br />

K(s’ ‘) = (1 + tK(s, 0))’<br />

This becomes infinite in finite time if K(s, 0) is anywhere negative and is analogous<br />

to shock formation experienced in the single scalar convex conservation law. ore<br />

precisely, consider the “viscous” conservation law <strong>with</strong> G concave, namely<br />

If we take E = 0 (the shock case), weak solutions to<br />

u, + CG(u)l, = 0<br />

4x, 0) = uob)

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