Botvinnik Semi-Slav, The (Pedersen)
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138 THE BOTVINNIK SEMI-SLAV<br />
(Piskov-S.Ivanov, Moscow 1986) 19<br />
liJe4 leads to a distinct advantage for<br />
White.<br />
c22) 13 ... i.g7 (voluntarily giving<br />
up on the defence of f7, but in return<br />
Black will get a few 'free' moves) 14<br />
i.xf7+ ~e7 15 f4. White could also<br />
return the bishop to h5, but it must be<br />
right to try to maintain the outpost on<br />
e5. Now we have:<br />
c221) 15 ... liJc6 16 0-0 liJxe5 17<br />
fxe5 'iWg5 18 d5! 'iVxe5 19 i.xe6 and<br />
White is gradually taking over, Tukmakov-Kuijf,<br />
Wijk aan Zee 1991.<br />
c222) 15 ... l:td8 16 0-0 b4 is interesting<br />
but this is only relevant if<br />
Black wants to play stubbornly for a<br />
win since line 'c223' looks fine for<br />
Black.<br />
c223) 15 ... i.xg2!? was Wells's preference<br />
in <strong>The</strong> Complete <strong>Semi</strong>-<strong>Slav</strong> and<br />
it must have been an awkward surprise<br />
when he was faced with it soon after<br />
his book was released! Wells-Lukacs,<br />
Budapest 1994 now went 16 l:tg1 h3<br />
17 'iWg4 (Wells had published his analysis<br />
this far) 17 ... liJd7! 18 i.xe6 (according<br />
to Lukacs, White can make a<br />
draw with 18 :'xg2! hxg2 19 i.xe6<br />
gl'iV+! 20'iVxg1 'iVh4+21 ~e2i.xe5!<br />
22 dxe5 '1txe6 23 'iVg6+ liJf6! 24 exf6<br />
l:thg8 25 'iWe4+ '1txf6 26 liJd5+ ~f7<br />
27 'iVf5+ but nothing more) 18 ... h5 19<br />
'iWg3 ~xe6 20 l:txg2 hxg2 21 'ii'h3+<br />
'iWf5 22 d5+ ~e7 23 d6+ ~e6 24<br />
'iWxg2 i.xe5 25 'iWd5+ ~f6 0-1.<br />
13liJxd7<br />
I also prefer Black after 13 liJe4<br />
i.b4+ 14 '1tfl 'iWf5 15liJxd7 ~xd7 16<br />
i.f3 '1tc8! 17 b3 :'d8, while Sadler's<br />
13 f4!? is best met by 13 ... b4 14 i.h5<br />
l:th7 15 liJe2 h3!?<br />
13 ... '1txd7 14 i.f3 a6 15 axb5<br />
I don't see why White should want<br />
to exchange many pieces in this line,<br />
so 15 0-0 looks like a better try, intending<br />
liJe4-c5, claiming that the<br />
two-pawn deficit does not mean that<br />
much as long as Black's light-squared<br />
bishop does not participate. However,<br />
Black seems to solve this problem by<br />
playing 15 ... i.g7! 16 axb5 (16 liJe4<br />
'iWxd4 gives White nothing) 16 ... axb5<br />
17liJxb5 :'xal18 'iWxal :'a8 19liJa3<br />
h3.<br />
15 ... axb5 16 lha8 i.xa8 17 'iVaI<br />
i.b7 18 'fJa7 '1tc8 19 0-0<br />
19 liJxb5 i.b4+ is very good for<br />
Black.<br />
19 ... l:tg8 20 i..e4 'iVf4 21 l:te1 f5<br />
Black has a winning advantage,<br />
Bellon-Lu.Perez, Havana Capablanca<br />
mem 1999.<br />
C3)<br />
1l ... h3!? (D)<br />
w