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p<br />

A <strong>fluid</strong> contained in<br />

a tank that is rotating<br />

with a constant<br />

angular velocity<br />

about an axis will<br />

rotate as a rigid<br />

body.<br />

z = constant<br />

dp<br />

dr<br />

dp ––– = rw 2 r<br />

dr<br />

r<br />

2.12.2 Rigid-Body Rotation<br />

2.12 Pressure Variation in a Fluid with Rigid-Body Motion 75<br />

After an initial “start-up” transient, a <strong>fluid</strong> contained in a tank that rotates with a constant angular<br />

velocity v about an axis as is shown in Fig. 2.30 will rotate with the tank as a rigid body. It is<br />

known from elementary particle dynamics that the acceleration of a <strong>fluid</strong> particle located at a distance<br />

r from the axis of rotation is equal in magnitude to rv 2 , and the direction of the acceleration<br />

is toward the axis of rotation, as is illustrated in the figure. Since the paths of the <strong>fluid</strong> particles<br />

are circular, it is convenient to use cylindrical polar coordinates r, u, and z, defined in the insert in<br />

Fig. 2.30. It will be shown in Chapter 6 that in terms of cylindrical coordinates the pressure gradient<br />

§p can be expressed as<br />

Thus, in terms of this coordinate system<br />

and from Eq. 2.2<br />

(2.29)<br />

(2.30)<br />

These results show that for this type of rigid-body rotation, the pressure is a function of two variables<br />

r and z, and therefore the differential pressure is<br />

or<br />

§p 0p<br />

0r ê r 1 r<br />

a r rv 2 ê r a u 0 a z 0<br />

0p<br />

0r rrv2<br />

0p<br />

0u 0<br />

0p<br />

0u ê u 0p<br />

0z ê z<br />

dp 0p 0p<br />

dr <br />

0r 0z dz<br />

dp rrv 2 dr g dz<br />

(2.31)<br />

On a horizontal plane (dz 0), it follows from Eq. 2.31 that dp dr 2 r, which is greater than<br />

zero. Hence, as illustrated in the figure in the margin, because of centrifugal acceleration, the pressure<br />

increases in the radial direction.<br />

Along a surface of constant pressure, such as the free surface, dp 0, so that from Eq. 2.31<br />

1using g rg2<br />

dz<br />

dr rv2<br />

g<br />

Integration of this result gives the equation for surfaces of constant pressure as<br />

z v2 r 2<br />

2g constant<br />

0p<br />

0z g<br />

<br />

(2.32)<br />

Axis of<br />

rotation<br />

z<br />

ω<br />

r<br />

ω<br />

2<br />

a r = r ω<br />

x<br />

θ<br />

r<br />

e z<br />

e<br />

y<br />

θ<br />

e r<br />

(a)<br />

F I G U R E 2.30<br />

(b)<br />

Rigid-body rotation of a liquid in a tank. (Photograph courtesy of Geno Pawlak.)<br />

(c)

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