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2.5 Measurement of Pressure 49<br />

p vapor<br />

A<br />

h<br />

p atm<br />

B<br />

Mercury<br />

F I G U R E 2.8<br />

Mercury barometer.<br />

Mercury<br />

Water<br />

noted that pressure differences are independent of the reference, so that no special notation is required<br />

in this case.<br />

The measurement of atmospheric pressure is usually accomplished with a mercury barometer,<br />

which in its simplest form consists of a glass tube closed at one end with the open end immersed<br />

in a container of mercury as shown in Fig. 2.8. The tube is initially filled with mercury<br />

1inverted with its open end up2 and then turned upside down 1open end down2, with the open end<br />

in the container of mercury. The column of mercury will come to an equilibrium position where<br />

its weight plus the force due to the vapor pressure 1which develops in the space above the column2<br />

balances the force due to the atmospheric pressure. Thus,<br />

p atm gh p vapor<br />

(2.13)<br />

where g is the specific weight of mercury. For most practical purposes the contribution of the vapor<br />

pressure can be neglected since it is very small [for mercury, p lbin. 2<br />

vapor 0.000023 1abs2 at<br />

a temperature of 68 °F], so that p atm gh. It is conventional to specify atmospheric pressure in<br />

terms of the height, h, in millimeters or inches of mercury. Note that if water were used instead of<br />

mercury, the height of the column would have to be approximately 34 ft rather than 29.9 in. of<br />

mercury for an atmospheric pressure of 14.7 psia! This is shown to scale in the figure in the margin.<br />

The concept of the mercury barometer is an old one, with the invention of this device attributed<br />

to Evangelista Torricelli in about 1644.<br />

E XAMPLE 2.3<br />

Barometric Pressure<br />

GIVEN A mountain lake has an average temperature of 10 °C and FIND Determine the absolute pressure 1in pascals2 at the deepest<br />

a maximum depth of 40 m. The barometric pressure is 598 mm Hg. part of the lake.<br />

SOLUTION<br />

The pressure in the lake at any depth, h, is given by the equation<br />

p gh p 0<br />

where p 0 is the pressure at the surface. Since we want the absolute<br />

pressure, p 0 will be the local barometric pressure expressed in a<br />

consistent system of units; that is<br />

p barometric<br />

g Hg<br />

and for g Hg 133 kNm 3<br />

598 mm 0.598 m<br />

p 0 10.598 m21133 kNm 3 2 79.5 kNm 2<br />

From Table B.2, g H2 O 9.804 kNm 3 at 10 °C and therefore<br />

p 19.804 kNm 3 2140 m2 79.5 kNm 2<br />

392 kNm 2 79.5 kNm 2<br />

472 kPa 1abs2<br />

(Ans)<br />

COMMENT This simple example illustrates the need for<br />

close attention to the units used in the calculation of pressure; that<br />

is, be sure to use a consistent unit system, and be careful not to<br />

add a pressure head 1m2 to a pressure 1Pa2.

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