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620 Chapter 11 ■ Compressible Flow<br />

For this example,<br />

or<br />

so that<br />

By using the value from Eq. 1 and Fig. D.2, we get<br />

and<br />

f 1/ 2 / 1 2<br />

D<br />

f 1/* / 12<br />

D<br />

10.02211 m2<br />

0.1 m 0.4 f 1/* / 22<br />

D<br />

f 1/* / 2 2<br />

0.2<br />

D<br />

Ma 2 0.70<br />

p 2<br />

p* 1.5<br />

f 1/* / 22<br />

D<br />

(1)<br />

(Ans)<br />

(2)<br />

We obtain<br />

p 2<br />

from<br />

p 2 a p 2<br />

p* b ap* p 1<br />

b a p 1<br />

p 0,1<br />

b 1p 0,1 2<br />

where p 2p* is given in Eq. 2 and p*p 1 , p 1p 0,1 , and p 0,1 are<br />

the same as they were in Example 11.12. Thus,<br />

p 2 11.52 a 1<br />

1.7 b 10.7623101 kPa1abs24<br />

68.0 kPa1abs2<br />

(Ans)<br />

COMMENT A larger back pressure [68.0 kPa1abs2] than the<br />

one associated with choked flow through a Fanno duct [45 kPa1abs2]<br />

will maintain the same flowrate through a shorter Fanno duct with<br />

the same friction coefficient. The flow through the shorter duct is not<br />

choked. It would not be possible to maintain the same flowrate<br />

through a Fanno duct longer than the choked one with the same friction<br />

coefficient, regardless of what back pressure is used.<br />

Rayleigh flow involves<br />

heat transfer<br />

with no wall friction<br />

and constant<br />

cross-sectional area.<br />

11.5.2 Frictionless Constant Area Duct Flow with Heat Transfer<br />

(Rayleigh Flow)<br />

Consider the steady, one-dimensional, and frictionless flow of an ideal gas through the constant<br />

area duct with heat transfer illustrated in Fig. 11.21. This is Rayleigh flow. Application of the<br />

linear momentum equation 1Eq. 5.222 to the Rayleigh flow through the finite control volume<br />

sketched in Fig. 11.21 results in<br />

01frictionless flow2<br />

or<br />

p 1 A 1 m # V 1 p 2 A 2 m # V 2 R x<br />

p 1rV22 constant<br />

(11.110)<br />

r<br />

Use of the ideal gas equation of state 1Eq. 11.12 in Eq. 11.110 leads to<br />

p 1rV22 RT<br />

constant<br />

(11.111)<br />

p<br />

Since the flow cross-sectional area remains constant for Rayleigh flow, from the continuity equation<br />

1Eq. 11.402 we conclude that<br />

rV constant<br />

For a given Rayleigh flow, the constant in Eq. 11.111, the density–velocity product, rV, and the<br />

ideal gas constant are all fixed. Thus, Eq. 11.111 can be used to determine values of <strong>fluid</strong> temperature<br />

corresponding to the local pressure in a Rayleigh flow.<br />

To construct a temperature–entropy diagram for a given Rayleigh flow, we can use Eq. 11.76,<br />

which was developed earlier from the second T ds relationship. Equations 11.111 and 11.76 can<br />

be solved simultaneously to obtain the curve sketched in Fig. 11.22. Curves like the one in Fig.<br />

11.22 are called Rayleigh lines.<br />

Frictionless and adiabatic<br />

converging–diverging duct<br />

Semi-infinitesimal<br />

control volume<br />

Frictionless duct with<br />

heat transfer<br />

Flow<br />

D = constant<br />

Section (1)<br />

Finite<br />

control volume<br />

Section (2)<br />

F I G U R E 11.21<br />

Rayleigh flow.

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