19.09.2019 Views

fluid_mechanics

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

11.5 Nonisentropic Flow of an Ideal Gas 615<br />

For Fanno flow, the<br />

Mach number is a<br />

function of the distance<br />

to the critical<br />

state.<br />

5.0<br />

The application of the energy equation 1Eq. 5.692 to Fanno flow gave Eq. 11.74. If Eq. 11.74 is<br />

differentiated and divided by temperature, the result is<br />

Substituting Eqs. 11.14, 11.36, and 11.46 into Eq. 11.91 yields<br />

which can be combined with Eq. 11.90 to form<br />

We can merge Eqs. 11.77, 11.79, and 11.90 to get<br />

Consolidating Eqs. 11.94 and 11.89 leads to<br />

Finally, incorporating Eq. 11.93 into Eq. 11.95 yields<br />

(11.91)<br />

(11.92)<br />

(11.93)<br />

(11.94)<br />

(11.95)<br />

(11.96)<br />

Equation 11.96 can be integrated from one section to another in a Fanno flow duct. We elect to<br />

use the critical 1*2 state as a reference and to integrate Eq. 11.96 from an upstream state to the critical<br />

state. Thus<br />

Ma*1<br />

Ma<br />

(11.97)<br />

where / is length measured from an arbitrary but fixed upstream reference location to a section in<br />

the Fanno flow. For an approximate solution, we can assume that the friction factor is constant at<br />

an average value over the integration length, /* /. We also consider a constant value of k. Thus,<br />

we obtain from Eq. 11.97<br />

1 11 Ma 2 2<br />

k 1<br />

k Ma 2 2k<br />

dT<br />

T d1V 2 2<br />

2c p T 0<br />

dT<br />

T k 1 Ma d1V 2 2<br />

2 0<br />

2 V 2<br />

d1V 2 2 d1Ma 2 2Ma 2<br />

<br />

V 2 1 31k 1224Ma 2<br />

dp<br />

p 1 d1V 2 2<br />

d1Ma2 2<br />

2 V 2 Ma 2<br />

1<br />

2 11 kMa2 2 d1V 2 2<br />

d1Ma2 2<br />

fk V 2 Ma 2 2<br />

11 Ma 2 2 d1Ma 2 2<br />

51 31k 1224Ma 2 6kMa f dx<br />

4 D<br />

Ma2<br />

dx<br />

D 0<br />

11 Ma 2 2 d1Ma 2 2<br />

51 31k 1224 Ma 2 6kMa /*<br />

4<br />

31k 1224Ma 2 f 1/* /2<br />

ln e<br />

2<br />

f <br />

1 31k 1224Ma D<br />

/<br />

f dx<br />

D<br />

(11.98)<br />

________ f(* – )<br />

D<br />

0.0<br />

0.1<br />

1.0<br />

Ma<br />

10<br />

For a given gas, values of f 1/* /2D can be tabulated as a function of Mach number for<br />

Fanno flow. For example, values of f 1/* /2D for air 1k 1.42 Fanno flow are graphed as a<br />

function of Mach number in Fig. D.2 in Appendix D and in the figure in the margin. Note that the<br />

critical state does not have to exist in the actual Fanno flow being considered, since for any two<br />

sections in a given Fanno flow<br />

f 1/* / 2 2<br />

D<br />

f 1/* / 12<br />

D<br />

f D 1/ 1 / 2 2<br />

(11.99)<br />

The sketch in Fig. 11.20 illustrates the physical meaning of Eq. 11.99.<br />

For a given Fanno flow 1constant specific heat ratio, duct diameter, and friction factor2 the<br />

length of duct required to change the Mach number from Ma 1 to Ma 2 can be determined from Eqs.<br />

11.98 and 11.99 or a graph such as Fig. D.2. To get the values of other <strong>fluid</strong> properties in the Fanno<br />

flow field we need to develop more equations.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!