fluid_mechanics
584 Chapter 11 ■ Compressible Flow If and are assumed to be constant for a given gas, Eqs. 11.19 and 11.20 can be integrated to get c p c v Changes in entropy are related to changes in temperature, pressure, and density. and s 2 s 1 c v ln T 2 T 1 R ln r 1 r 2 (11.21) s 2 s 1 c p ln T 2 T 1 R ln p 2 p 1 (11.22) Equations 11.21 and 11.22 allow us to calculate the change of entropy of an ideal gas flowing from one section to another with constant specific heat values 1 and 2. c p c v E XAMPLE 11.2 Entropy for an Ideal Gas GIVEN Consider the air flow of Example 11.1. FIND Calculate the change in entropy, s 2 s 1 , between sections 112 and 122. SOLUTION Assuming that the flowing air in Fig. E11.1 behaves as an ideal gas, we can calculate the entropy change between sections by using either Eq. 11.21 or Eq. 11.22. We use both to demonstrate that the same result is obtained either way. From Eq. 11.21, To evaluate s 2 s 1 from Eq. 1 we need the density ratio, r 1r 2 , which can be obtained from the ideal gas equation of state 1Eq. 11.12 as and thus from Eqs. 1 and 2, s 2 s 1 c v ln T 2 T 1 R ln r 1 r 2 By substituting values already identified in the Example 11.1 problem statement and solution into Eq. 3 with a p 1 T 1 b a T 2 p 2 b a r 1 r 2 a p 1 T 1 b a T 2 p 2 b s 2 s 1 c v ln T 2 T 1 R ln ca p 1 T 1 b a T 2 p 2 bd 100 psia 540 °R b a 453 °R 18.4 psia b 4.56 (1) (2) (3) we get or or s 2 s 1 3133 1ft # lb21lbm # 453 °R °R24 ln a 540 °R b 353.3 1ft # lb21lbm # °R24 ln 4.56 From Eq. 11.22, s 2 s 1 57.5 1ft # lb21lbm # °R2 s 2 s 1 c p ln T 2 R ln p 2 T 1 p 1 By substituting known values into Eq. 4 we obtain s 2 s 1 3186 1ft # lb21lbm # 453 °R °R24 ln a 540 °R b 18.4 psia 353.3 1ft # lb21lbm # °R24 ln a 100 psia b s 2 s 1 57.5 1ft # lb21lbm # °R2 (Ans) (4) (Ans) COMMENT As anticipated, both Eqs. 11.21 and 11.22 yield the same result for the entropy change, s 2 s 1 . Note that since the ideal gas equation of state was used in the derivation of the entropy difference equations, both the pressures and temperatures used must be absolute. If internal energy, enthalpy, and entropy changes for ideal gas flow with variable specific heats are desired, Eqs. 11.4, 11.8, and 11.19 or 11.20 must be used as explained in Ref. 2. Detailed tables 1see, for example, Ref. 32 are available for variable specific heat calculations. The second law of thermodynamics requires that the adiabatic and frictionless flow of any fluid results in ds 0 or s 2 s 1 0. Constant entropy flow is called isentropic flow. For the isentropic flow of an ideal gas with constant and c v , we get from Eqs. 11.21 and 11.22 c p c v ln T 2 T 1 R ln r 1 r 2 c p ln T 2 T 1 R ln p 2 p 1 0 (11.23)
By combining Eq. 11.23 with Eqs. 11.14 and 11.15 we obtain 11.2 Mach Number and Speed of Sound 585 a T k1k12 2 b a r k 2 b a p 2 b T 1 r 1 p 1 (11.24) which is a useful relationship between temperature, density, and pressure for the isentropic flow of an ideal gas. From Eq. 11.24 we can conclude that p r k constant (11.25) for an ideal gas with constant c p and c v flowing isentropically, a result already used without proof earlier in Chapters 1, 3, and 5. F l u i d s i n t h e N e w s Hilsch tube (Ranque vortex tube) Years ago (around 1930) a French physics student (George Ranque) discovered that appreciably warmer and colder portions of rapidly swirling air flow could be separated in a simple apparatus consisting of a tube open at both ends into which was introduced, somewhere in between the two openings, swirling air at high pressure. Warmer air near the outer portion of the swirling air flowed out one open end of the tube through a simple valve and colder air near the inner portion of the swirling air flowed out the opposite end of the tube. Rudolph Hilsch, a German physicist, improved on this discovery (ca. 1947). Hot air temperatures of 260 °F (127 °C) and cold air temperatures of 50 °F (46 °C) have been claimed in an optimized version of this apparatus. Thus far the inefficiency of the process has prevented it from being widely adopted. (See Problems 11.80.) 11.2 Mach Number and Speed of Sound Mach number is the ratio of local flow and sound speeds. The Mach number, Ma, was introduced in Chapters 1 and 7 as a dimensionless measure of compressibility in a fluid flow. In this and subsequent sections, we develop some useful relationships involving the Mach number. The Mach number is defined as the ratio of the value of the local flow velocity, V, to the local speed of sound, c. In other words, Ma V c What we perceive as sound generally consists of weak pressure pulses that move through air with a Mach number of one. When our ear drums respond to a succession of moving pressure pulses, we hear sounds. To better understand the notion of speed of sound, we analyze the one-dimensional fluid mechanics of an infinitesimally thin, weak pressure pulse moving at the speed of sound through a fluid at rest 1see Fig. 11.1a2. Ahead of the pressure pulse, the fluid velocity is zero and the fluid pressure and density are p and r. Behind the pressure pulse, the fluid velocity has changed by an amount dV, and the pressure and density of the fluid have also changed by amounts dp and dr. We select an infinitesimally thin control volume that moves with the pressure pulse as is sketched Weak pressure pulse Weak pressure pulse p ρ V = 0 c Control volume p + δρ ρ + δρ δV p ρ c Control volume p + δρ ρ + δρ c – δV A A A A (a) (b) F I G U R E 11.1 (a) Weak pressure pulse moving through a fluid at rest. (b) The flow relative to a control volume containing a weak pressure pulse.
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584 Chapter 11 ■ Compressible Flow<br />
If and are assumed to be constant for a given gas, Eqs. 11.19 and 11.20 can be integrated to get<br />
c p<br />
c v<br />
Changes in entropy<br />
are related to<br />
changes in temperature,<br />
pressure, and<br />
density.<br />
and<br />
s 2 s 1 c v ln T 2<br />
T 1<br />
R ln r 1<br />
r 2<br />
(11.21)<br />
s 2 s 1 c p ln T 2<br />
T 1<br />
R ln p 2<br />
p 1<br />
(11.22)<br />
Equations 11.21 and 11.22 allow us to calculate the change of entropy of an ideal gas flowing from<br />
one section to another with constant specific heat values 1 and 2.<br />
c p<br />
c v<br />
E XAMPLE 11.2<br />
Entropy for an Ideal Gas<br />
GIVEN Consider the air flow of Example 11.1.<br />
FIND Calculate the change in entropy, s 2 s 1 , between sections<br />
112 and 122.<br />
SOLUTION<br />
Assuming that the flowing air in Fig. E11.1 behaves as an ideal<br />
gas, we can calculate the entropy change between sections by using<br />
either Eq. 11.21 or Eq. 11.22. We use both to demonstrate that<br />
the same result is obtained either way.<br />
From Eq. 11.21,<br />
To evaluate s 2 s 1 from Eq. 1 we need the density ratio, r 1r 2 ,<br />
which can be obtained from the ideal gas equation of state<br />
1Eq. 11.12 as<br />
and thus from Eqs. 1 and 2,<br />
s 2 s 1 c v ln T 2<br />
T 1<br />
R ln r 1<br />
r 2<br />
By substituting values already identified in the Example 11.1<br />
problem statement and solution into Eq. 3 with<br />
a p 1<br />
T 1<br />
b a T 2<br />
p 2<br />
b a<br />
r 1<br />
r 2<br />
a p 1<br />
T 1<br />
b a T 2<br />
p 2<br />
b<br />
s 2 s 1 c v ln T 2<br />
T 1<br />
R ln ca p 1<br />
T 1<br />
b a T 2<br />
p 2<br />
bd<br />
100 psia<br />
540 °R<br />
b a<br />
453 °R<br />
18.4 psia b 4.56<br />
(1)<br />
(2)<br />
(3)<br />
we get<br />
or<br />
or<br />
s 2 s 1 3133 1ft # lb21lbm #<br />
453 °R<br />
°R24 ln a<br />
540 °R b<br />
353.3 1ft # lb21lbm # °R24 ln 4.56<br />
From Eq. 11.22,<br />
s 2 s 1 57.5 1ft # lb21lbm # °R2<br />
s 2 s 1 c p ln T 2<br />
R ln p 2<br />
T 1 p 1<br />
By substituting known values into Eq. 4 we obtain<br />
s 2 s 1 3186 1ft # lb21lbm #<br />
453 °R<br />
°R24 ln a<br />
540 °R b<br />
18.4 psia<br />
353.3 1ft # lb21lbm # °R24 ln a<br />
100 psia b<br />
s 2 s 1 57.5 1ft # lb21lbm # °R2<br />
(Ans)<br />
(4)<br />
(Ans)<br />
COMMENT As anticipated, both Eqs. 11.21 and 11.22 yield<br />
the same result for the entropy change, s 2 s 1 .<br />
Note that since the ideal gas equation of state was used in the<br />
derivation of the entropy difference equations, both the pressures<br />
and temperatures used must be absolute.<br />
If internal energy, enthalpy, and entropy changes for ideal gas flow with variable specific heats<br />
are desired, Eqs. 11.4, 11.8, and 11.19 or 11.20 must be used as explained in Ref. 2. Detailed tables<br />
1see, for example, Ref. 32 are available for variable specific heat calculations.<br />
The second law of thermodynamics requires that the adiabatic and frictionless flow of any <strong>fluid</strong><br />
results in ds 0 or s 2 s 1 0. Constant entropy flow is called isentropic flow. For the isentropic<br />
flow of an ideal gas with constant and c v , we get from Eqs. 11.21 and 11.22<br />
c p<br />
c v ln T 2<br />
T 1<br />
R ln r 1<br />
r 2<br />
c p ln T 2<br />
T 1<br />
R ln p 2<br />
p 1<br />
0<br />
(11.23)